Answer:
∠x = 90°
∠y = 58°
∠z = 32°
Step-by-step explanation:
he dimensions of the angles given are;
∠B = 32°
Whereby ΔABC is a right-angled triangle, and the square fits at angle A, we have;
∠A = 90°
∠B + ∠C = 90° which gives
32° + ∠C = 90°
∠C = 58°
∠x + Interior angle of the square = 180° (Sum of angles on a straight line)
∠x + 90° = 180°
∠x = 90°
∠x + ∠y + 32° = 180° (Sum of angles in a triangle)
90° + ∠y + 32° = 180°
∠y = 180 - 90° - 32° = 58°
∠y + ∠z + Interior angle of the square = 180° (Sum of angles on a straight line)
58° + ∠z +90° = 180°
∴ ∠z = 32°
∠x = 90°
∠y = 58°
∠z = 32°
Answer: x = 40.81 or 41
Step-by-step explanation:
A = B = 21
C = 35
Hypotenuse = x
Calculating Hypotenuse:
21^2 + 35^2 = x^2
=> 441 + 1225 = x^2
=> x^2 = 1666
=> x = 40.81 or 41
Answer:
The solution is given in attached diagram:
The restrictions for the equation is that the denominator can not be zero. So the restrictions for x would be what values make the denominator zero.
7x^2 + 6x = 0
factor
x(7x + 6) = 0
multiply any number by 0 and you get 0. So either x = 0 or 7x+6 = 0
since there's a x in the numerator x/x = 1 so this will not be a restriction. Then the only restriction is:
7x+6 = 0
7x = -6
x = -6/7
Answer:
C = 37.7
r = 6
Length - 0.740
Ok thanks for the points!
