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bezimeni [28]
3 years ago
12

Ella and her children went into a bakery and where they sell cookies for $0.50 each and brownies for $2.25 each. Ella has $15 to

spend and must buy a minimum of 9 cookies and brownies altogether. If Ella decided to buy 5 cookies, determine the maximum number of brownies that she could buy. If there are no possible solutions, submit an empty answer.
Mathematics
2 answers:
Mice21 [21]3 years ago
6 0

Answer:

If each cookie is .50 and she wants to buy 5 cookies @ .50= $2.50

Than subtract $2,50 from $15.00 (which she has to spend you have $12.50

Then divide 2.25 into $12.5 and you get an answer of 5 brownies with a $1.30 extra to spend

Step-by-step explanation:

matrenka [14]3 years ago
5 0

Answer: 5 brownies

Step-by-step explanation:

cookies = 5 x $0.50 = $2.5

$15 - $2.5 = $12.5

$12.5 divided by $2.25 = $5.555

so at the most ella can buy 5 brownies if she buys 5 cookies

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2 years ago
A triangle has a perimeter of 48 feet. If the three sides of the triangle are n, 4n−2, and 4n−4, what is the length of each side
alexdok [17]

Answer:

6; 22; 20 (ft.)

Step-by-step explanation:

1) if the length of the each side are: n; 4n-2 and 4n-4, then the expression of the perimeter can be written: P=n+4n-2+4n-4 or P=9n-6.

2) if according to the condition perimeter is 48 (ft.), then

9n-6=P; ⇔ 9n-6=48; n=6.

3) if n=6, then the required lengths of the sides are:

n=6 (ft.);

4n-2=22 (ft.);

4n-4=20 (ft.)

3 0
2 years ago
The Pew Research Center reported that 73% of Americans who own a cell phone also use text messaging. In a recent local survey, 1
AnnZ [28]

Answer:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

Step-by-step explanation:

Information provided

n=200 represent the sample size slected

X=155 represent the cell phone owners used text messaging

\hat p=\frac{155}{200}=0.775 estimated proportion of cell phone owners used text messaging

p_o=0.73 is the value to verify

\alpha=0.1 represent the significance level

We need to conduct a z test for a proportion

z would represent the statistic

p_v represent the p value

System of hypothesis

We want to verify if the true proportion of cell phone owners used text messaging is different from 0.73 so then the system of hypothesis are:

Null hypothesis:p=0.73  

Alternative hypothesis:p \neq 0.73  

The statistic to check this hypothesis is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.775 -0.73}{\sqrt{\frac{0.73(1-0.73)}{200}}}=1.433  

Now we can find the p value. Since we have a bilateral test the p value would be:  

p_v =2*P(z>1.433)=0.152  

Since the p value is higher than the significance level of 0.1 we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:

Do Not reject H0

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A flower pot has a circumference of 47 inches. What is the approximate length of the radius of the flower pot? Use 3.14 for .
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Answer:

7.48

Step-by-step explanation:

C=2πr

Solving for

r=C

2π=47

2·π≈7.48028

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