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Llana [10]
3 years ago
11

Please solve the equation:4(y-3)=3(y+6) and please show your work!

Mathematics
1 answer:
dalvyx [7]3 years ago
6 0
4(y-3)=3(y+6)
1) Distribute
4y-12=3y+18
2) Addition property of equality
4y=3y+30
3)Subtraction property of equality
y=30
Thats your answer!
Enjoy middle school while you still can!
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A population of values has a normal distribution with μ = 157.7 and σ = 57 . You intend to draw a random sample of size n = 24 .
alexgriva [62]

Answer:

z=1.64

And if we solve for a we got

a=157.7 +1.64*57=251.18

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Step-by-step explanation:

Previous concepts

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Solution to the problem

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X \sim N(157.7,57)  

Where \mu=157.7 and \sigma=57

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=157.7 +1.64*57=251.18

So the value of height that separates the bottom 95% of data from the top 5% is 251.18.  

5 0
3 years ago
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4 0
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