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GrogVix [38]
3 years ago
8

If the area of a triangular kite is 6 square feet and its base is 4 feet, find the height

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0
The height of the kite is 3 feet. Here’s
why;
We know that BH=2A (base times height is equal to 2 times the area) of any given triangle.
Lets plug in values;
BH=2A
4(H)=2(6)
Then simplify;
4(H)=12
Flip the equation to find the missing value;
12 divided by 4 is 3.
Check your work;
4(3)=6(2):
12=12
The height of the kite is 3 feet.
You might be interested in
Which of these characteristics do a rhombus and a rectangle always have in common?
lutik1710 [3]

Answer:

opposite sides with equal length

hope it helps

7 0
3 years ago
Read 2 more answers
A storage tank will have a circular base of radius r and a height of r. The tank can be either cylindrical or hemispherical​ (ha
Neko [114]

Answer:

Volume: \frac{2}{3}\pi r^3

Ratio: \frac{2}{9}r

Step-by-step explanation:

First of all, we need to find the volume of the hemispherical tank.

The volume of a sphere is given by:

V=\frac{4}{3}\pi r^3

where

r is the radius of the sphere

V is the volume

Here, we have a hemispherical tank: a hemisphere is exactly a sphere cut in a half, so its volume is half that of the sphere:

V'=\frac{V}{2}=\frac{\frac{4}{3}\pi r^3}{2}=\frac{2}{3}\pi r^3

Now we want to find the ratio between the volume of the hemisphere and its surface area.

The surface area of a sphere is

A=4 \pi r^2

For a hemisphere, the area of the curved part of the surface is therefore half of this value, so 2\pi r^2. Moreover, we have to add the surface of the base, which is \pi r^2. So the total surface area of the hemispherical tank is

A'=2\pi r^2 + \pi r^2 = 3 \pi r^2

Therefore, the ratio betwen the volume and the surface area of the hemisphere is

\frac{V'}{A'}=\frac{\frac{2}{3}\pi r^3}{3\pi r^2}=\frac{2}{9}r

6 0
3 years ago
Can an expert help with this
SVEN [57.7K]

The formula of an area of a circle:

A_O=\pi r^2

We have

r = 1.8 m

π ≈ 3.14

Substitute:

A_O=\pi\cdot1.8^2=3.24\pi\ m^2\approx3.24\cdot3.14=10.1736\ m^2\approx10.17\ m^2

7 0
3 years ago
I need help one this one
8_murik_8 [283]
56 in squared I believe!
3 0
3 years ago
In which quadrant is (-1/2, -1.8)?
andrey2020 [161]
X = -1/2 (negative)
y = - 1.8 (negative)

so It's in Quadrant 3
5 0
3 years ago
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