The correct answer is 4 :-)
Remark
A kite is constructed such that AB = BC and AD = DC. AB = sqrt( (1/2)AC + 18^2) see diagram. AD = sqrt(24^2 + 32^2)
Step One
Solve for AB
1/2 AC = 24 (AC is given as 48)
18 is a given length
AB = sqrt(24^2 + 18^2) = sqrt(576 + 324) = sqrt(900) = 30
Step Two
Find the length of AD
AD = sqrt(32^2 + 24^2) = sqrt(1024 + 576) = sqrt(1600) = 40
Step Three
Find the Perimeter.
P = 2 * 30 + 2*40 = 60 + 80 = 140
P = 140 <<<<< Answer
Edit to reflect comments:
3^-1=1/3
4^-1=1/4
Flip the fraction over basically i.e. 4/1---->1/4
Let the full marks = x
Then, it would be: x*40/100 = 60
x = 6000/40
x = 150
Full marks will be 150
Answer:
From the above image when the input of f(x) is 9 the output is 1
So f^-1(1) is just the reverse when the input is 1 the output is 9
So f^-1(1) = 9
Hope this helps
