<span>(2^1/2x2^3/4)^2
</span><span> ((2^1/2)(2^3/4))^2
</span> ((2^1/2)^2)((2^3/4)^2)
(2)(2^3/2)
(4*2^3)^(1/2)
(2*2*2^3)^(1/2)
(*2^5/2)
The answer for this case is
b. <span>sqrt 2^5</span>
Since ED and DB are exactly half of EB, we can set ED and DB equal to each other.
x + 4 = 3x - 8
Subtract x from both sides. Add 8 to both sides
12 = 2x
Divide both sides by 2
6 = x
ED = 6 + 4 = 10
ED = DB = 10
EB = ED +DB = 10 + 10 = 20
ED = 10
DB = 10
EB = 20
Let
x--------> <span>the rectangle's length
y-------> </span><span>the rectangle's width
we now that
Area of rectangle=x*y
Area=256 cm</span>²
<span>256=x*y-------> equation 1
y=4x-48------> y=4x-48------> equation 2
substitute equation 2 in equation 1
256=x*[4x-48]-----> 256=4x</span>²-48x
4x²-48x-256=0
<span>
using a graph tool----> to resolve the second order equation
see the attached figure
the solution is
x=16 cm
y=4x-48----> y=4*16-48-----> y=16 cm
is a square
the answer is</span>
the rectangle's length is 16 cm
I think 15 I am not 100 percent on that
There are no true statements at all on the list you provided.