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Maru [420]
3 years ago
7

Please help!!!! Whoever answers these three questions correctly first will get brainliest answer!!!!!

Mathematics
2 answers:
inna [77]3 years ago
4 0
4. -8
5. 24
6. I can't see it properly so if it's ÷ answer is 9 if it's - answer is -70
vladimir2022 [97]3 years ago
3 0
4. original = 12 degrees
Rose by 8 degrees
12+8= 20
drop by 28 degrees
20-28= -8 degrees.
So the answer is -8°.


5. (-6) * (-4) = 24

when a negative times a negative, the result will turn positive.


6. I believe it's a divide sign, ➗
-63 / -7 = 9
when a negative divides by a negative, the result turns positive.

But if it's a positive sign, than it's -70.
-63 + -7= -70
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Sam paid $8.28 for 18 stamps.at this rate,how much would it cost Sam to buy 12 stamps
allsm [11]

Answer: It costs $5.52 to Sam to buy 12 stamps.


Step-by-step explanation:

Given: Sam paid $8.28 for 18 stamps.

Thus, the cost of 18 stamps = $8.28

Then the cost of 1 stamp=\frac{8.28}{18}

Thus, the cost of 1 stamp=$0.46

With the same rate , the cost of 12 stamps=0.46\times12

Therefore, the cost of 12 stamps= $5.52

hence, it costs $5.52 to Sam to buy 12 stamps.

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How do I do this equation? Need help please <br> Will mark brainliest
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Given the equation y − 3 = one half(x + 6) in point-slope form, identify the equation of the same line in standard form.
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C.y=1/2x+6, is fit....
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Solve the system by elimination.(show your work)
PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

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