Part A) Find BC, the distance from Tower 2 to the plane, to the nearest foot.
in the triangle ACD
sin16=CD/(7600+BD)--------> CD=sin16*(7600+BD)---------> equation 1
in the triangle BCD
sin24=CD/BD-----------> CD=sin24*BD---------------> equation 2
equation 1=equation 2
sin16*(7600+BD)=sin24*BD-----> sin16*7600+sin16*BD=sin24*BD
sin24*BD-sin16*BD=sin16*7600----> BD=[sin16*7600]/[sin24-sin16]
BD=15979 ft
in the triangle BCD
cos24=BD/BC---------> BC=BD/cos24-------> 15979/cos24-------> 17491
BC=17491 ft
the answer part 1) BC is 17491 ft
Part 2) Find CD, the height of the plane from the ground, to the nearest foot.
CD=sin24*BD ( remember equation 2)
BD=15979 ft
CD=sin24*15979 -----------> CD=6499 ft
the answer part 2) CD is 6499 ft
Answer:
huh????
Step-by-step explanation:
what did you try to say
The answer would be 45. Thank you very much and good luck on there!
Transformation.. If you're referring to geometry
Answer:20π
Step-by-step explanation:
equation of the circle
(x+3)² + (y-5)² = r²
now, (-9, -3) lies on it
So, (-9+3)² + (-3-5)² =r²
36+ 64 = r² =100
hence, r =10
So, circumference = 2πr = 20π
