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Alex Ar [27]
3 years ago
6

What is the complement of angle 41?

Mathematics
1 answer:
Darina [25.2K]3 years ago
8 0
49 is the complement to 41. Complementary angles add up to 90 degrees.
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A cycle race began at 9:40
Ksenya-84 [330]
The entire race took Henry 1hr:36min which is 96min. He has an average speed of 30km/hr means he's been traveling 0.5km/min
30km/hr > 30km/1hr >
30km/60min = 0.5km/min
since Henry took 96min to finish the race we multiply 0.5km/min with 96
0.5km/min*96min=48km
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3 years ago
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PLEASE HELP FAST PLEASE AND THANK YOU HELP MY SISTER MEH
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The answers are B , D , and F
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3 years ago
Verb dale had a total of 45.8 inches of rain this year. This year's total was 7.48 inches greater than last year's total. What w
Delvig [45]
1. 45.8-7.48=38.32 in

2. 5/6-3/4=10/12-9/12= 1/12 miles farther
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SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR
slega [8]

Answer:

1)

A)

We must use the formula b x h/2  12 x 8/2 = 48    

A=48

B)

We must use the formula 1/2a root c squared - a squared

Solving and substituing will get you 35.78

2)

A)

We must divide 81 by 2 to get 9. Since this is a square, all sides will be 9. Then, we must add 9 four times to get 36 cm as our perimeter

B) If we draw the square with a diagonal line, we can understand that the diagonal line (hypotenus) is  s root 2.

3) The formula for this area of a triangle is h x b/2. We must substitute the numbers to get our answer:

h x b /2 = 10 x 20/2 = 200/2 = 100

AREA IS 100cm squared

Step-by-step explanation:

5 0
3 years ago
a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di
Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}

Thus, the total prototypes will cost around $60.75

7 0
1 year ago
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