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ozzi
3 years ago
12

Can you please help me with this question

Mathematics
1 answer:
Sergeeva-Olga [200]3 years ago
6 0
Hirap nyan ah hahahahah
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The table represents a proportional relationship the equation y=2/15x represents another proportional relationship. Of these two
scZoUnD [109]
I think it's A. I can't really see the graphs clearly. It's the one that crosses at (15,2)
8 0
3 years ago
I will give brainliest to the correct answers! yep that's YOU
siniylev [52]

Answer: Yes, because the amount of money you save for every beverage bought is constant, and if you buy 0 beverages, you’ll save $0. That means it the situation is graphed, the line produced will be linear and crosses through the origin, which are the requirements for a proportional relationship.

3 0
2 years ago
The perimeter of this rectangle is 24cm. If the length is 8 cm, what is the height?
Gemiola [76]

Answer:

4

Step-by-step explanation:

P = s+s+s+s

length = 8

8x2=16

24-16=8

8 / 2 = 4

3 0
3 years ago
Read 2 more answers
Q5: Identify the graph of the equation and write an equation of the translated or rotated graph in general form.
MAVERICK [17]

Answer:

d.\:ellipse;\:3x^2+y^2+6x-6y+3=0.

Step-by-step explanation:

The given conic has equation;

3x^2+y^2=9

Divide through by 9.

\Rightarrow \frac{3x^2}{9}+\frac{y^2}{9}=\frac{9}{9}

\Rightarrow \frac{x^2}{3}+\frac{y^2}{9}=1.

This is an ellipse centered at the origin;

This ellipse has been translated so that the center is now at;

(-1,3)

The translated ellipse has equation;

\frac{(x+1)^2}{3}+\frac{(y-3)^2}{9}=1.

Clear the fraction;

3(x+1)^2+(y-3)^2=9.

Expand;

3(x^2+2x+1)+(y^2-6y+9)=9.

3x^2+6x+3+y^2-6y+9=9.

Write in general form;

3x^2+y^2+6x-6y+9-9+3=0.

3x^2+y^2+6x-6y+3=0.

The correct choice is D

4 0
3 years ago
Read 2 more answers
If f(x)3(=- Vx-3, complete the following statement:x + 2f(19) ==Answer here
Digiron [165]
Explanation

This exercise is about evaluating a function at a particular argument. To do that, we replace the variable with the argument in the formula of the function, and simplify.

Let's do that:

\begin{gathered} f(19)=\frac{3}{19+2}-\sqrt[]{19-3}, \\  \\ f(19)=\frac{3}{21}-\sqrt[]{16}, \\  \\ f(19)=\frac{1}{7}-4, \\  \\ f(19)=\frac{1-28}{7}, \\  \\ f(19)=-\frac{27}{7}\text{.} \end{gathered}Answerf(19)=-\frac{27}{7}\text{.}

8 0
1 year ago
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