PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
2 answers:
So the y-int is 1 so it has the intercept the y axis at 0,1. Then it’s a curved line since it’s the sqrt of x. So the answer is bottom left one.
Answer: (C) <em>bottom left graph </em>
<u>Step-by-step explanation:</u>
f(x)=2√x + 1
The number inside the square root symbol must be greater than or equal to zero, so there is a restriction on x. x ≥ 0
The only graphs that satisfy this restriction are graphs C and D.
The restriction on "x" creates a restriction on "y". Since x≥0, then:
f(0) ≥ 2√0 + 1
f(0) ≥ 1
So, y must be greater than or equal to 1. The only graph that satisfies thie restriction is the graph on the bottom left.
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Answer:
I believe its the second one but i could be wrong
Yes
Step-by-step explanation:
its a direct-variation function
Try solving it on your own
3x+2 mulitiply by 2. you will get 6x+4 now put 10x-12 like so 6x+4=10x-12. then use like terms and subtract 6x from 10x. you will get 4x-12=4. then add 12 to cancel out then divide 16 by 4 and then x=4 then plug in 4 to replace x in 3x+2.
The error was in second step.
3√(y^3)^4 = y^4
(Cube root cancels cube and not power 4)
The answer should be:
xy^4/4
//Hope it helps.
