4 years ago

Given: ∠BCD ≅ ∠EDC and ∠BDC ≅ ∠ECD Prove: Δ BCD ≅ Δ EDC

Mathematics

1 answer:

never [62]4 years ago

3 0

It would be bisecting angles

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Find the area please don’t lie to me

astra-53 [7]

Answer:

Step-by-step explanation:

The formula of an area of a trapezoid:

$A=\dfrac{b_1+b_2}{2}\cdot h$

<em>b₁, b₂</em><em> - bases</em>

<em>h</em><em> - height</em>

From the picture we have

$b_1=19yd,\ b_2=5yd,\ h=9yd$

Substitute:

$A=\dfrac{19+5}{2}\cdot9=\dfrac{24}{2}\cdot9=12\cdot9=108\ yd^2$

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4 years ago

Do all of these PLEASE

swat32

Answer:

9= .8

10= .2

11= 4

12= 1/3

13= -2

14= -2/3

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part 2

1. 10

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3. -5

4. -13

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3 years ago

zahra cuts a loaf of bread into 5 equal pieces she then cuts each piece into 3 equal slices what fraction of the whole loaf is o

jarptica [38.1K]

One slice of bread would be 1/15

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3 years ago

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romanna [79]

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4 years ago

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The line integral of xydx×x^2y^3dy where c is the triangle with points (0,0) (1,0) (1,2) using green's theorem

lyudmila [28]

If $\mathcal C$ is the boundary of the triangle $D$ , then by Green's theorem

$\displaystyle\int_{\mathcal C}xy\,\mathrm dx+x^2y^3\,\mathrm dy=\iint_D\left(\frac{\partial(x^2y^3)}{\partial x}-\frac{\partial(xy)}{\partial y}\right)\,\mathrm dA$
$=\displaystyle\int_{x=0}^{x=1}\int_{y=0}^{y=2x}(2xy^3-x)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x\int_{y=0}^{y=2x}(2y^3-1)\,\mathrm dy\,\mathrm dx$
$=\displaystyle\int_{x=0}^{x=1}x(8x^4-2x)\,\mathrm dx=\frac23$

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3 years ago