All categories

3 years ago

I need help on this question

Mathematics

1 answer:

max2010maxim [7]3 years ago

4 0

Answer A
21 mm
7 x 3 = 21

You might be interested in

Simplify the next two expressions

prisoha [69]

1. 7x-40
2. 8x-30y-10

4 0

3 years ago

Gabby is going to see Disney on ice there are 12 people going to Disney on ice. Gabby pays $24.50 for each ticket to Disney on i

algol [13]

First, you have to multiply 12×24.50=$360.00. Next, you have to subtract 372.75-360.00=12.75. Then, you have to divide 12.75÷5=$2.55. So in conclusion, each lightsaber costs $2.55.

7 0

3 years ago

the mass of a crate of mangoes is 11 12/13 kilograms. the mass of a crate of pineapples is 11 11/12 kilograms. write an inequali

aleksley [76]

11/12/13 Kg (mangoes) is heavier than 11/11/12 Kg (pineapples)

6 0

3 years ago

Each flight uses a jet with a capacity of 180 seats. The airline measures the utilization of the aircraft by passenger load. Pas

garri49 [273]

<h2>Answer:</h2>

(a). 5400

(b). 57 - 0.95, 85 - 0.48 and 94 - 0.44

(c). Less load in Flight number 85 and 94.

<h2>Step-by-step explanation:</h2>

In the question,

Number of seats in a jet = 180

And,

$Passenger\,Load=\frac{Number\,of\,seats\,sold}{Number\,of\,available\,seats}$

Now,

Flight Number 57 has seats sold = 5130

Flight Number 85 has seats sold = 2592

Flight Number 94 has seats sold = 2376

(a).

Available seat capacity for each flight number in June can be found out by,

Number of days in the month of June = 30 days

Each day the flight has = 180 seats.

So,

Total number of available seat capacity for each flight in June is = 180 x 30 = 5400

Therefore, available seat capacity for each flight = 5400

(b).

Passenger load for each flight can be given by,

For Flight number 57,

$Passenger\,Load=\frac{Number\,of\,seats\,sold}{Number\,of\,available\,seats}\\Passenger\,Load=\frac{5130}{5400}\\Passenger\,Load=0.95$

For Flight number 85,

$Passenger\,Load=\frac{Number\,of\,seats\,sold}{Number\,of\,available\,seats}\\Passenger\,Load=\frac{2592}{5400}\\Passenger\,Load=0.48$

For Flight number 94,

$Passenger\,Load=\frac{Number\,of\,seats\,sold}{Number\,of\,available\,seats}\\Passenger\,Load=\frac{2376}{5400}\\Passenger\,Load=0.44$

(c).

The recommendation for the Eastern skies can be that the Passenger Load in the Flight number 57 is near to perfect.

But, the Passenger Load in Flight number 85 and 94 is less than required so there is need of selling more seats in the respective airline flights.

8 0

3 years ago

Solve the problem using rate x time = distance

Finger [1]

17 - 3 hours
18 - 11 kilometers per hour
19 - Each ticket cost is 9.45
20 - 6 bags

6 0

3 years ago

Read 2 more answers