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3 years ago

HELPPP PLLZZZZ MY school gonna KILL MEEE

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

7 0

Answer:

1. X = 4

2. N = 9

3. B = 5

Too lazy to do 4.

Step-by-step explanation:

1. find the value of X, by simply trying to find a LCD (Lowest Common Denominator) and then you... Yeah too lazy. It's simple to figure out....

2. same thing as 1..

3. 18 over 3, 30 over b, find the value of b.

4. same thing as 3..

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Can you help me with this?<br> (I will give one of you brainliest)

Degger [83]

Answer:

1) $\sqrt{9}$ and $\sqrt{16}$ (between 3 and 4)

Explanation: $\sqrt{9}$ and $\sqrt{16}$ are the closest WHOLE squares root to $\sqrt{12}$ ; any other square roots wouldn't give us a whole number, or they're farther away from

2) $-\sqrt{144}$ and $-\sqrt{169}$ (between -(12) and -(13))

3) $-\sqrt{36}$ and $-\sqrt{49}$ (between -(6) and -(7))

8 0

3 years ago

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What does 45 dividend by 5/11

Galina-37 [17]

Answer:

i think the answer is 99 im not completely sure though

but i hope this helps

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3 years ago

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The formula for any geometric sequence is a n = a 1 · r n - 1 , where a n represents the value of the nth term, a 1 represents t

AfilCa [17]

Answer:

Step-by-step explanation:instead, try making the subscripts and superscripts stand out:

n-1

a = a * r

n n-1

Believe me, it's worth the extra work to do this!!

Given the sequence -3, -6, -12, -24, you can easily see that the first term,

a is -3. The common factor is 2. Note how (-3)*2=-6, and so on.

So, a = -3 and r=2.

So the formula for this geometric sequence is

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8 0

3 years ago

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A(R+T)=W solve for T

Leni [432]

A(R+T)=W
(A×R)+(A×T)=W
AR+AT=W
-AR from both sides
AT=W-AR
divide both sides by A
T=(W-AR)/A

6 0

3 years ago

For every integer k from 1 to 10, inclusive the "k"th term of a certain sequence is given by (−1)(k+1)∗(12k). If T is the sum of

Katena32 [7]

Answer:

Option D. is the correct option.

Step-by-step explanation:

In this question expression that represents the kth term of a certain sequence is not written properly.

The expression is $(-1)^{k+1}(\frac{1}{2^{k}})$ .

We have to find the sum of first 10 terms of the infinite sequence represented by the expression given as $(-1)^{k+1}(\frac{1}{2^{k}})$ .

where k is from 1 to 10.

By the given expression sequence will be $\frac{1}{2},\frac{(-1)}{4},\frac{1}{8}.......$

In this sequence first term "a" = $\frac{1}{2}$

and common ratio in each successive term to the previous term is 'r' = $\frac{\frac{(-1)}{4}}{\frac{1}{2} }$

r = $-\frac{1}{2}$

Since the sequence is infinite and the formula to calculate the sum is represented by

$S=\frac{a}{1-r}$ [Here r is less than 1]

$S=\frac{\frac{1}{2} }{1+\frac{1}{2}}$

$S=\frac{\frac{1}{2}}{\frac{3}{2} }$

S = $\frac{1}{3}$

Now we are sure that the sum of infinite terms is $\frac{1}{3}$ .

Therefore, sum of 10 terms will not exceed $\frac{1}{3}$

Now sum of first two terms = $\frac{1}{2}-\frac{1}{4}=\frac{1}{4}$

Now we are sure that sum of first 10 terms lie between $\frac{1}{4}$ and $\frac{1}{3}$

Since $\frac{1}{2}>\frac{1}{3}$

Therefore, Sum of first 10 terms will lie between $\frac{1}{4}$ and $\frac{1}{2}$ .

Option D will be the answer.

3 0

3 years ago