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Sergio039 [100]
3 years ago
14

How many particles are there in 1.43 g of a molecular compound with a gram molecular mass of 233g

Chemistry
1 answer:
dalvyx [7]3 years ago
7 0
<span>1.43g x (1 mole / 233g) x (6.022x10^23 particles / mole) =  3.70 x 10^ 21 particles</span>
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Kinetic energy <br><br>definition:<br><br><br>sentence: ​
Irina18 [472]

Answer:

Kinetic energy , is the energy of an object possessed due to it's motion

Explanation:

Kinetic energy is the energy of mass in motion. The kinetic energy of an object is the energy it has because of its motion.

it's formula ½mv²

7 0
3 years ago
One of relatively few reactions that takes place directly between two solids at room temperature is In this equation, the in Ba(
yuradex [85]

Answer:

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate.

Explanation:

Ba(OH)_2.8H_2O(s)+NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+8H_2O(l)+NH_3(g)

The balance chemical equation is :

Ba(OH)_2.8H_2O(s)+2NH_4SCN(s)\rightarrow Ba(SCN)_2(s)+10H_2O(l)+2NH_3(g)

Mass of barium hydroxide octahydrate = 6.5 g

Moles of  barium hydroxide octahydrate = \frac{6.5 g}{315 g/mol}=0.020635 mol

According to reaction, 2 moles of ammonium thiocyanate reacts with1 mole of  barium hydroxide octahydrate. The 0.020635 moles of barium hydroxide octahydrate will react with:

\frac{2}{1}\times 0.020635 mol=0.04127 mol

Mass of 0.04127 moles of ammonium thiocyanate;

0.04127 mol\times 76 g/mol=3.136 g\approx 3.14 g

3.14 grams of ammonium thiocyanate must be used to react completely with 6.5 g barium hydroxide octahydrate

3 0
4 years ago
When a 0.4500 g sample of impure potassium chloride was dissolved in water and treated with an excess ofsilver nitrate, 0.8402 g
Svetllana [295]

Answer:

97.78% KCl in the original sample

Explanation:

5 0
3 years ago
Ammonia, NH3, is a typical ingredient in household cleaners. It is produced through a combination reaction involving N2(g) and H
GalinKa [24]
The balanced chemical reaction is:

N2 + 3H2 = 2NH3

We are given the amount of hydrogen gas to be used in the reaction. This will be the starting point of the calculations.

24.0 mol H2 (2 mol NH3 / 3 mol H2 ) = 16 mol NH3

Therefore, ammonia produced from the reaction given is 16 moles.
3 0
4 years ago
How many molecules of NH3 are produced from 4.72x10 negative 4 power g of H2?
Delvig [45]
<span>9.40x10^19 molecules.
   The balanced equation for ammonia is:
 N2 + 3H2 ==> 2NH3
   So for every 3 moles of hydrogen gas, 2 moles of ammonia is produced. So let's calculate the molar mass of hydrogen and ammonia, starting with the respective atomic weights:
 Atomic weight nitrogen = 14.0067
  Atomic weight hydrogen = 1.00794

   Molar mass H2 = 2 * 1.00794 = 2.01588 g/mol
 Molar mass NH3 = 14.0067 + 3 * 1.00794 = 17.03052 g/mol

   Moles H2 = 4.72 x 10^-4 g / 2.01588 g/mol = 2.34140921086573x10^-4 mol
   Moles NH3 = 2.34140921086573x10^-4 mol * (2/3) = 1.56094x10^-4 mol

Now to convert from moles to molecules, just multiply by Avogadro's number: 1.56094x10^-4 * 6.0221409x10^23 = 9.400197448261x10^19
   Rounding to 3 significant figures gives 9.40x10^19 molecules.</span>
7 0
3 years ago
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