Answer: 100.3 mmHg
Explanation:
Given that:
Volume of nitrogen gas V = 4.200 L
Temperature T = 21°C
Convert Celsius to Kelvin
(21°C + 273 = 294K)
Pressure P = ?
Number of moles of gas = 0.02300
Molar gas constant R is a constant with a value of 0.0821 atm L K-1 mol-1
Then, apply ideal gas equation
pV = nRT
p x 4.200L = 0.02300 moles x (0.0821 atm L K-1 mol-1 x 294K)
p x 4.200L = 0.555 atm L
p = 0.555 atm L / 4.200L
p = 0.132 atm
Now, convert pressure in atm to mmHg
If 1 atm = 760 mmHg
0.132 atm = (0.132 x 760) = 100.3 mmHg
Thus, 100.3 mmHg of pressure is required
Please provide more of the question so I am able to answer, but I do know that H20 has 0 calories.
Answer:
K.E = 0.5 j
Explanation:
Given data:
Mass of ball = 50 g (50/1000 =0.05 kg)
Speed of ball = 4.5 m/s
K.E of ball = ?
Solution:
Formula:
K.E = 1/2 m.v²
Now we will put the values in formula
K.E = 1/2 (0.05 kg) (4.5 m/s)²
K.E = 1/2 (0.05 kg) 20.25 m²/s²
K.E = 1/2 (1.0 kg. m²/s²)
K.E = 0.5 kg. m²/s²
j = kg. m²/s²
K.E = 0.5 j
Answer:
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