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Tresset [83]
3 years ago
10

A 3cm² sector of an angle and radians o and r respectively has total perimeter of 7m.Find the possible values of o and r.

Mathematics
1 answer:
Paha777 [63]3 years ago
5 0
Im sorry i just need points
lol
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5. Find the radius of a cylinder with a volume of 150 in^3<br> and a height of 10 in.
kvasek [131]

Answer:

Hi there!

The correct answer is: 2.185 in

Step-by-step explanation:

The formula for the volume of cylinder is: V= Base * Height

where base is π * radius²

So given that information, we can first divide 10 on sides to get πr²= 15

then divide pi on both sides to get 4.7746 then square root both sides to get

r=2.185

7 0
3 years ago
Braydon is performing the four arithmetic operations on 14 and 2.
Studentka2010 [4]
Well, let's just solve all these darn operations!

<em>14 + 2 = 16
</em><em>14 - 2 = 12
</em><em>14 * 2 = 28
</em><em>14 / 2 = 7
</em>
<em />So, what do you think the answer is? =)
7 0
3 years ago
Quien me ayuda?porfa ;-;​
asambeis [7]

I don't understand your language sorry

3 0
3 years ago
Tell how the Communicative property of addition and the Associative property of addition can help solve the problem mentally 8+(
topjm [15]

Step-by-step explanation:

Communicative property states that, in addition, integers added in any order will still give the same answer.

So in this question,

rather than first adding 8 + (-5), we add 8 + (-8)

We know that a number + its additive Inverse (opposite sign) is equal to zero

And we know any number added to zero is equal to the number.

So we can quickly find out that the sum is -5

4 0
3 years ago
Read 2 more answers
May someone help me with this question please anyone please
djverab [1.8K]
5;\ 5;\ 5;\ 5;\ 7;\ 9\\\\\overline{x}=\dfrac{5+5+5+5+7+9}{6}=\dfrac{36}{6}=6\\\\\delta^2=\dfrac{(x_1-\overline{x})^2+(x_2-\overline{x})^2+(x_3-\overline{x})^2+...+(x_n-\overline{x})^2}{n}\\\\\delta^2=\dfrac{(5-6)^2+(5-6)^2+(5-6)^2+(5-6)^2+}{6}
\dfrac{+(7-6)^2+(9-6)^2}{6}\\\\\delta^2=\dfrac{(-1)^2+(-1)^2+(-1)^2+(-1)^2+1^2+3^2}{6}=\dfrac{14}{6}=\dfrac{7}{3}

standard\ deviation:\\\\\sqrt{\delta^2}=\sqrt{\dfrac{7}{3}}=\dfrac{\sqrt7}{\sqrt3}=\dfrac{\sqrt7\cdot\sqrt3}{\sqrt3\cdot\sqrt3}=\boxed{\dfrac{\sqrt{21}}{3}}\approx\boxed{1.53}
4 0
4 years ago
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