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RideAnS [48]
3 years ago
15

Which best explains why the equation 3x + 8 = 3x - 5 has no solutions?

Mathematics
2 answers:
never [62]3 years ago
6 0

Answer:c

Step-by-step explanation:

Bas_tet [7]3 years ago
4 0
The best answer for the question is C - The equation is not true for any value of x.

The reason for this is if we subtract 3x from both sides, there are no variables left. since there are no variables left, we know since first grade that 8 does not equal to -5....with that being true, there is no value we can assign to x to make this a true statement.
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Which expression is equivalent to (5x^3)(2x)^3
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Answer:

\large\boxed{(5x^3)(2x)^3=40x^6}

Step-by-step explanation:

(5x^3)(2x)^3\qquad\text{use}\ (ab)^n=a^nb^n\\\\(5x^3)(2^3x^3)=(5x^3)(8x^3)\qquad\text{use commutative law}\\\\=(5\cdot8)(x^3x^3)\qquad\text{use}\ a^na^m=a^{n+m}\\\\=40x^{3+3}=40x^6

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3 years ago
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kipiarov [429]

Answer: Id say b

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3 years ago
If h (x) = {(-2,3), (0,4), (1,6), (2, 9)}<br><br> then what set of values represent h-1 (x) ?
vfiekz [6]

Answer:

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

Step-by-step explanation:

Given: h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

To find: h^{-1}(x)

Solution:

A relation is said to be a function if each and every element of the domain has a unique image in the co-domain.

Inverse of a function exist if it is both one to one and onto.

h(x)=\{(-2,3),(0,4),(1,6),(2,9)\}

h^{-1}(x)=\{(3,-2),(4,0),(6,1),(9,2)\}

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