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3 years ago

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A rental company charges a flat fee of $25 and an additional $0.40 per mile to rent a car. Has to be a linear equation.

1 answer:

Yanka [14]3 years ago

5 0

To make this a linear equation, you would do this:

It starts off already of you spent $25, even with 0 miles, so the y-intercept would be 25.

The slope would be .40x, while x = additional miles.

In the slope intercept form, it would be y = .40x + 25

The graph would be: https://puu.sh/zPyHV/880c02e660.png

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10² = ?<br><br> What is 10² = to?<br><br> Thanks in advance. :P

romanna [79]

To answer this exponent we will multiply the base by the power. Lets do it:-

10 = base
2 = power

10² = 10 × 10 = 100
10² = 100

CHECK OUR WORK:-

√100 = 10

We were RIGHT!!!

So, 10² = 100.

Hope i helped ya!! :)

8 0

3 years ago

Read 2 more answers

For what value of k is there one solution to the given quadratic equation (k+1)x²+4kx+2=0.

andriy [413]

Answer:

If $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = (x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

The signal of $\bigtriangleup$ determines how many real roots an equation has:

$\bigtriangleup > 0$ : Two real and different solutions

$\bigtriangleup = 0$ : One real solution

$\bigtriangleup < 0$ : No real solutions

In this problem, we have the following second order polynomial:

$(k+1)x^{2} + 4kx + 2 = 0$ .

This means that $a = k+1; b = 4k; c = 2$

It has one solution if

$\bigtriangleup = 0$

$b^{2} - 4ac = 0$

$16k^{2} -8(k+1) = 0$

$16k^{2} - 8k - 8 = 0$

We can simplify by 8

$2k^{2} - k - 1 = 0$

The solution is:

$k = 1$ or $k = -\frac{1}{2}$

So, if $k = 1$ or $k = -\frac{1}{2}$ , there is only one solution to the given quadratic equation.

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3 years ago