increase kinetic energy of body
Answer:
Explanation:
Force of friction at car B ( break was applied by car B ) =μ mg = .65 x 2100 X 9.8 = 13377 N .
work done by friction = 13377 x 7.30 = 97652.1 J
If v be the common velocity of both the cars after collision
kinetic energy of both the cars = 1/2 ( 2100 + 1500 ) x v²
= 1800 v²
so , applying work - energy theory ,
1800 v² = 97652.1
v² = 54.25
v = 7.365 m /s
This is the common velocity of both the cars .
To know the speed of car A , we shall apply law of conservation of momentum .Let the speed of car A before collision be v₁ .
So , momentum before collision = momentum after collision of both the cars
1500 x v₁ = ( 1500 + 2100 ) x 7.365
v₁ = 17.676 m /s
= 63.63 mph .
( b )
yes Car A was crossing speed limit by a difference of
63.63 - 35 = 28.63 mph.
Answer:
It is number two
Explanation:
beacause a star cluster is a bunch of stars held together by gravity
5.8 moles of nitrogen gas are needed to pressurize the air bag.
<h3>What's the expression of Ideal gas equation?</h3>
- Ideal gas equation is PV=nRT
- P= pressure, V = volume, n= no. of moles of gas, R= universal gas constant, T = temperature of the gas
<h3>What's the no. of moles of nitrogen present in a 60L air bag at 2.37 atm pressure and 25°C temperature?</h3>
- P= 2.37 atm, V = 60L, R= 0.0821 L-atm/mol-K, T = 25°C = 298K
- n= PV/RT
= (2.37×60)/(0.0821×298)
= 5.8 moles
Thus, we can conclude that 5.8 moles of nitrogen gas are needed to pressurize the air bag.
Learn more about the ideal gas here:
brainly.com/question/20348074
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