Answer
Initial radius of the artery is (1.1 cm) / 2 = 0.55 cm
final radius of the artery is (0.90 cm) / 2 = 0.45 cm
initial velocity of the blood is 17 cm/s
Using equation of continuity is
A₁v₁=A₂v₂
π r₁² x v₁ = π r₂² x v₂
r₁² x v₁ = r₂² x v₂
0.55² x 17 =0.45² x v₂
v₂=25.39 cm/s
Bernoulli's equation is
rho is the density of blood = 1060 kg/m^3
Answer:
Explanation:
This is a simple Law of Momentum Conservation problem of the inelastic type. The equation for this is
Filling in:
which simplifies to
5400 + 0 = 3300v
so v = 1.6 m/s to the east, choice B
Answer:
true
Explanation:
because the bonds in that element can only be shared but not transferred , but sometimes it depends on the element
Answer:
250 m
Explanation:
Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.
Hence, sqrt(150^2+200^2) = 250 m.
Hope this helped!
Answer: 90.1 s
Explanation:
Use equation for power:
P=F*V
Use eqation for force:
F=ma
F---force
V---velocity
Vr=om/s
V=30m/s
m=1000kg
P=10000W
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P=FV
F=P/V
F=10000W/30m/s
F=333.33N
Use equation for force to find accelartaion.
F=ma
a=F/m
a=333.33N/1000kg
a=0.333 m/s²
Use equation for accelaration to find out time:
a=(V-Vs)/t
t=(V-Vs)/a
t=(30m/s)/(0.333m/s²)
t=90.09 s≈90.1 s
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