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Bess [88]
4 years ago
10

A leaf floating down from a tree is an example of an object in free fall.

Physics
1 answer:
Nuetrik [128]4 years ago
7 0

Answer:

Oi, mate its false

Explanation:

because if an leaf floats down from a tree it is not considered an object for a free-fall

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The buildup of plaque on the walls of an artery may decrease its diameter from 1.1 cm to 0.90 cm. The speed of blood flow was 17
natka813 [3]

Answer

Initial radius of the artery is (1.1 cm) / 2 = 0.55 cm

final radius of the artery is (0.90 cm) / 2 = 0.45 cm

initial velocity of the blood is 17 cm/s

Using  equation of continuity is

                                      A₁v₁=A₂v₂

                                 π r₁² x v₁ = π r₂² x v₂

                                  r₁² x v₁ = r₂² x v₂

                                  0.55² x 17 =0.45² x v₂

                                        v₂=25.39 cm/s

Bernoulli's equation is

P_1 - P_2 = \dfrac{1}{2}\rho (v_2^2-v_1^2)

rho is the density of blood = 1060 kg/m^3

P_1 - P_2 = \dfrac{1}{2}\times 1060 \times (0.254^2-0.17^2)

P_1 - P_2 =18.87\ Pa

6 0
3 years ago
A 1200 kg car traveling east at 4.5 m/s crashes into the side of a 2100 kg truck that is not moving. During the collision, the v
Rasek [7]

Answer:

Explanation:

This is a simple Law of Momentum Conservation problem of the inelastic type. The equation for this is

[m_1v_1+m_2v_2]_b=[(m_1+m_2)v]_a  Filling in:

[1200(4.5)+2100(0)]=[(1200+2100)v] which simplifies to

5400 + 0 = 3300v

so v = 1.6 m/s to the east, choice B

6 0
3 years ago
True or false? If an element can form covalent bonds then it will never be involved in ionic bonding.
vladimir2022 [97]

Answer:

true

Explanation:

because the bonds in that element can only be shared but not transferred , but sometimes it depends on the element

7 0
3 years ago
Read 2 more answers
A man goes 150 m due east and then 200 m due north how far is he from starting point
grin007 [14]

Answer:

250 m

Explanation:

Since North and East are 90 degrees from each other, we can treat this as a right-angled triangle, with the distance in each direction being the sides and the distance from the starting point being the hypotenuse.

Hence, sqrt(150^2+200^2) = 250 m.

Hope this helped!

7 0
3 years ago
How long does a car (1000 kg) have a speed of 30 m/s from a rest if the engine power is 10kw
Lemur [1.5K]

Answer: 90.1 s

Explanation:

Use equation for power:

P=F*V

Use eqation for force:

F=ma

F---force

V---velocity

Vr=om/s

V=30m/s

m=1000kg

P=10000W

---------------------------

P=FV

F=P/V

F=10000W/30m/s

F=333.33N

Use equation for force to find accelartaion.

F=ma

a=F/m

a=333.33N/1000kg

a=0.333 m/s²

Use equation for accelaration to find out time:

a=(V-Vs)/t

t=(V-Vs)/a

t=(30m/s)/(0.333m/s²)

t=90.09 s≈90.1 s

------------------------

5 0
3 years ago
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