Answer:
2.13m/s^2
Explanation:
Use equation:
Fnet=ma
If 17.7 is the netto force (Fnet) then you just substitute the values in and solve.
Note m is mass (kg) and a is acceleration (m/s^2)
The outer core is made out of molten lava also known as liquid metal because of all the iron and other metals in it
Answer:
8 Hz, 48 Hz
Explanation:
The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.
The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

where
is the fundamental frequency
In this problem, we know that the wave's third harmonic has a frequency of

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

Now we can also find the frequency of the 6-th harmonic using n = 6:

The work and energy theorem allows finding the result for where the kinetic energy of the car is before stopping is:
The energy becomes:
- An important part in work on discs.
- A part in non-conservative work due to friction.
Work is defined by the scalar product of force and displacement.
W = F . d
Where the bold indicate vectors, W is work, F is force and d is displacement.
The work energy theorem relates work and kinetic energy.
W = ΔK =
In this case the vehicle stops therefore its final kinetic energy is zero, consequently the work is:
W = - K₀
Therefore, the initial kinetic energy that the car has is converted into work in its brakes. In reality, if assuming that there is friction, an important part is transformed into non-conservative work of the friction force, this work can be seen in a significant increase in the temperature of the discs on which the work is carried out.
In conclusion, using the work-energy theorem we can find the result for where the kinetic energy of the car is before stopping is:
The energy becomes:
- An important part in work on the discs.
- A part in non-conservative work due to friction.
Learn more here: brainly.com/question/17056946