A 1540-kg truck has a wheel base of 3.13 m (this is the distance between the front and rear axles). The center of mass of the tr
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Answer:
Speed of ball just before it hit the surface is 31.62 m/s .
Explanation:
Given :
Mass of ball , m = 50 g = 0.05 kg .
Height from which it falls , h = 80 m .
Thermal energy , E = 15 J .
Now , Initial energy of the system is :
Here , initial velocity is zero .
Therefore ,
Now , final energy of the system :
Since , no external force is applied .
Therefore , total energy of the system will be constant .
By conservation of energy :
Therefore , speed of ball just before it hit the surface is 31.62 m/s .
Explanation:
It is given that,
Velocity of particle 1, u₁ = 10 m/s
Velocity of particle 2, u₂ = 5 m/s
Let v₁ and v₂ are the final speed of both particles after the collision. Applying the conservation of momentum as :
......................(1)
For an elastic collision, the coefficient of restitution is equal to 1 as :
................(2)
On solving equation (1) and (2), we get,
So, the speeds of particle 1 and particle 2 after the collision is 5 m/s and 10 m/s respectively. Hence, this is the required solution.