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soldier1979 [14.2K]

3 years ago

15

11 more than y please help

1 answer:

mel-nik [20]3 years ago

8 0

$to\ obtain \ 11 \ more\ than\ y\ we\ add\ 11\ to\ y:\\\\Rusult:\\y+11$

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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)

maxonik [38]

Answer with Step-by-step explanation:

We are given that

$r(t)=< t^2,\frac{2}{3}t^3,t >$

We have to find T,N and B at the given point t > (1, $2/3$ ,1)

$r'(t)=$

$\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1$

$T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}$

Now, substitute t=1

$T(1)=\frac{}{2+1}=\frac{1}{3}$

$T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}$

$T'(1)=-\frac{4}{9}+\frac{1}{3}$

$T'(1)=\frac{1}{9}=$

$\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}$

$N(1)=\frac{T'(1)}{\mid T'(1)\mid}$

$N(1)=\frac{}{\frac{2}{3}}=$

$N(1)=$

$B(1)=T(1)\times N(1)$

$B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}$

$B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})$

$B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k$

$B(1)=\frac{1}{3}$

5 0

3 years ago

Can u show me how to solve this problem 0.11 times 0.91

lisov135 [29]

Answer:

0.1001

Step-by-step explanation: Your answer is 0.1001

0.91

<u> 0.11</u>

1011

0990

<u>00000</u>

0.1001

Hope this helps you!!! :)

3 0

3 years ago

GUYS IM GONNA CRY BECAUSE I SUCK AT ANSWERING WORD PROBLEMS SO PLS HELP ME I'll give u brainliest a thanks and 5 starss, Sorry t

Dmitrij [34]

Vas happenin!!

The last option is correct… She flipped the Y values and the X values it would be 4-12÷9-7

Hope this helps

-Zayn Malik

4 0

2 years ago

Find the slope of the line that passes through the points f(4) = 6 and f(-2) = 8.

leonid [27]

Answer:

slope = - $\frac{1}{3}$

Step-by-step explanation:

given f(4) = 6 and f(- 2) = 8 , then 2 points on the line are

(4, 6 ) and (- 2, 8 )

calculate slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (4, 6 ) and (x₂, y₂ ) = (- 2, 8 )

m = $\frac{8-6}{-2-4}$ = $\frac{2}{-6}$ = - $\frac{1}{3}$

6 0

2 years ago

Picking up a hot coal is wich type of heat transfer

NeTakaya

A) conduction. because you are conducting heat from the coal to your hand

8 0

3 years ago

Read 2 more answers