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saveliy_v [14]
3 years ago
15

He ages of mark and adam add up to 28 years total. mark is 20 years older than adam. how many years old is adam

Mathematics
1 answer:
OverLord2011 [107]3 years ago
6 0
You divide and ur answer is 8 

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542 increased by 1/4 of itself is?
Bas_tet [7]
542(1+1/4)

542(4/4+1/4)

542(5/4)

677.5


5 0
3 years ago
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How do I decease 7 by 3%​
FromTheMoon [43]

Answer:

6.79

Step-by-step explanation:

First of all, you will have to know how much is 3% of 7 in order to decrease it by that amount.

7 x 0.03 = 0.21

Now that you know the amount, you can subtract it from seven and therefore you have decreased 7 by 3%.

7 - 0.21 = 6.79

3 0
2 years ago
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Select all the pairs of equivalent expressions.
iren2701 [21]

Answer:

\huge\boxed{(3^4)^4=3^8\cdot3^8}\\\boxed{4^3\cdot5^3=20^3}\\\boxed{(4^3)^3=4^3\cdot4^3\cdo4^3}

Step-by-step explanation:

a^n\cdot a^n=a^{n+m}\\\\(a^n)^m=a^{n\cdot m}\\\\(a\cdot b)^n=a^n\cdot b^n\\=====================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3=4^{3+3}=4^6\\\\4^9\neq4^6\to(4^3)^3\neq4^3\cdot4^3\\==================

(3^4)^4=3^{4\cdot4}=3^{16}\\3^8\cdot3^8=3^{8+8}=3^{16}\\\\(3^4)^4=3^8\cdot3^8\\================

6^4\cdot3^4=(6\cdot3)^4=18^4\\\\18^4\neq18^8\to6^4\cdot3^4\neq18^8\\=================

4^3\cdot5^3=(4\cdot5)^3=20^3\\\\4^3\cdot5^3=20^3\\=================

(4^3)^3=4^{3\cdot3}=4^9\\4^3\cdot4^3\cdot4^3=4^{3+3+3}=4^9\\\\(4^3)^3=4^3\cdot4^3\cdot4^3

3 0
3 years ago
What is 2(3x+15) - (8+2x) simplified
Olin [163]

Answer:

4x+22

Step-by-step explanation:

<3

Brainliest?

3 0
3 years ago
Read 2 more answers
30 Points please help!! Please explain too!
sergiy2304 [10]
Initial: 200 feet = opp. side
Angle = 17.31, adj. Side = a
So tan (17.31) = opp. Side / adj. Side
tan (17.31) = 200 / a
--> a = 200/tan17.31 = 641.73
When stopped: adj. Still = a
Opp. Side still = 200, angle = 46.41
tan46.41 = 200 / a
--> a = 200/tan46.41 = 190.39
Now subtract those two distances to get the distance traveled from initial to when it stopped:
641.73 - 190.39 = 451.34 feet
3 0
3 years ago
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