Question

Please help me with this problem:)

Answer 1

Answer:

(2,1)

Step-by-step explanation:

3x+y = 7

-2x +y = -3

Solve the second equation for y by adding 2x to each side

-2x+2x +y = -3+2x

y = -3 +2x

Substitute into the first equation

3x+ (-3+2x) = 7

Combine like terms

5x -3 = 7

Add 3 to each side

5x-3+3 = 7+3

5x = 10

Divide by 5

5x/5 = 10/5

x=2

Now we need to solve for y

y = -3 +2x

y = -3 +2(2)

y = -3+4

y =1

Answer 2

Step-by-step explanation:

$3x + y = 7 \: \: \: \: \: \: ...(1) \\ - 2x + y = - 3 \: \: \: \: \: \: \: ...(2)$

From (1) we get,

$x = \frac{7 - y}{3}$

put the value of x in equation 2

$- 2( \frac{7-y}{3} ) + y = - 3 \\ \\ - \frac{14 -2y}{3} + y = - 3 \\ \\ \frac{ - 14 -2y+ 3y}{3} = - 3 \\ \\ y - 14 = - 9 \\ y = + 14 - 9 \\ y = 5$

Now,

put the value of y in equation (1)

$3x + ( - 23) = 7 \\ 3x - 23 = 7 \\ 3x = 7 + 23 \\ 3x = 30 \\ \\ x = \frac{30}{3} \\ \\ x = 10$