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2 years ago

Y'= x.e^x/ (1+y).y giải pt vi phân cấp 1

Mathematics

1 answer:

Rasek [7]2 years ago

5 0

I’m just trying to get my stuff done can you help me please help

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There are a total of 127 cars and trucks in a lot. If there are four more than twice the number of tricks than cars, how many ca

Kruka [31]

There are a total of 127 cars on a lot if there are four more than twice the number of trucks than cars how any trucks and cars are on the lot

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3 years ago

8q + 6 = 4q - 14<br> Please help

ICE Princess25 [194]

Answer:

q=-5

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Can someone please help me with math.

Umnica [9.8K]

Answer:

9) C. 35 + 0.12x = 44.36

10) B

11) A. 32

Step-by-step explanation:

44.36 is the TOTAL so the equations have to EQUAL it.

PER mile means it's a variable so it's 0.12x:

35 is a constant so there's no variable attached:

35 + 0.12x = 44.36

10)

B because you have to cancel the y values and to do that, you multiply the 1st equation by 3.

11)

0.1x + 0.25(46 - x) = 6.70

0.1x + 11.5 - 0.25x = 6.7

-0.15x = 6.7 - 11.5

-0.15x = -4.8

x = 32

5 0

3 years ago

Megan and Heidi are making cookies for an upcoming bake sale. Megan is making chocolate chip cookies and Heidi is making sugar c

koban [17]

Answer:

Heidi (260 cookies)

Step-by-step explanation:

Megan's equation is given as y=8x, where x is the number of bags, and y the number of cookies:

#First calculate Heidi's total number of bags, cookies and cookies:

$H_b=\sum{bags}\\\\=10+12+14+16\\\\=52 \ bags\\\\H_c=\sum{cookies}\\\\=50+60+70+80\\\\=260 \ cookies$

#Given that both Heidi and Megan make the same number of bags of cookies, Megan's cookies totals to:

$H_b=M_B=52 \ Bags\\\\M_c=y=8x, x=52\\\\y=8\times 52\\\\=416\\$

Hence, Megan makes 416 cookies.

#From our calculations:

$416>260\\\\M_c>H_c$

Hence, Heidi makes the least number of cookies(260 cookies) compared to Megan's 416 cookies.

7 0

3 years ago

What is the center and radius of the circle?<br> (x-3)2 + y² = 4

Kipish [7]

Answer:

center = (3, 0)

radius = 2

Step-by-step explanation:

Standard equation of a circle: $\sf (x-h)^2+(y-k)^2=r^2$

(where (h, k) is the center of the circle and r is the radius)

Given equation:

$\sf (x-3)^2+y^2=4$

Rewrite in standard form:

$\sf \implies (x-3)^2+(y-0)^2=2^2$

Therefore

center = (3, 0)
radius = 2

4 0

2 years ago