The intervals which represents those in which case the function, f(x) is reducing are as follows; [–2.5, –2], [–2, –1.5], [1.5, 2], [2, 2.5].

<h3>Which intervals naming the answer choices show the function f(x) decreasing?</h3>

It follows from the complete task content that the x-intervals between which the function value of f(x) is reducing are to be identified from the graph as attached.

On this note, by observation on the graph, it follows that from between the interval; [–2.5, –2], the function f(x) is decreasing.

Also, between the interval; [–2, –1.5], the function f(x) is decreasing.

Also, between the interval; [1.5, 2], the function f(x) is decreasing.

Also, between the interval; [2, 2.5], the function f(x) is decreasing.

Remark: The answer choices are as follows; [–2.5, –2] [–2, –1.5] [–1, 1] [1.5, 2] [2, 2.5) [2.5, 3]

Read more on decreasing intervals;

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4 0

2 years ago

Jacey obtains a 30-year 6/2 ARM at 4% with a 2/6 cap structure in the amount of $224,500. What is the monthly payment during the

beks73 [17]

In this case we have an ARM fixed for 6 years and adjust after the initial first 6 years every 2 years after. The basic idea behind a ARM is that the interest changes periodically, but since our ARM is fixed for 6 years, our going to calculate the monthly payment during the initial period using the formula: $m= \frac{P( \frac{r}{12}) }{1-(1+ \frac{r}{12})^{-12t} }$
where
$m$ is the monthly payment
$P$ is the amount
$r$ is the interest rate in decimal form
$t$ is the number years

First we need to convert our interest rate of 4% to decimal form by dividing it by 100%:
$\frac{4}{100} =0.04$
We also know from our question that $P=224500$ and $t=30$ , so lets replace those values into our formula to find the monthly payment:
$m= \frac{224500( \frac{0.04}{12}) }{1-(1+ \frac{0.04}{12})^{-(12)(30)} }$
$m=1071.80$

We can conclude that the monthly payment during the initial period is $1071.58<span />

7 0

3 years ago