Answer:
0.01
Steps:
The definition of "reciprocal" is simple. To find the reciprocal of any number, just calculate "1 ÷ (that number)." For a fraction, the reciprocal is just a different fraction, with the numbers "flipped" upside down (inverted). For instance, the reciprocal of 3/4 is 4/3
 
        
                    
             
        
        
        
Answer:
Dimensions will be 
Length = 7.23 cm
Width = 7.23 cm
Height = 9.64 cm
Step-by-step explanation:
A closed box has length = l cm
width of the box = w cm
height of the box = h cm
Volume of the rectangular box = lwh 
504 = lwh

Sides which involve length and width and height, cost = 3 cents per cm²
Top and bottom of the box costs = 4 cents per cm²
Cost of the sides  = 3[2(l + w)h] = 6(l + w)h
= 3[2(l + w)h] = 6(l + w)h
 = 3[2(l + w)h]
= 3[2(l + w)h]

Cost of the top and the bottom  = 4(2lw) = 8lw
= 4(2lw) = 8lw
Total cost of the box C =  + 8lw
 + 8lw
                                       = ![3024[\frac{1}{l}+\frac{1}{w}]](https://tex.z-dn.net/?f=3024%5B%5Cfrac%7B1%7D%7Bl%7D%2B%5Cfrac%7B1%7D%7Bw%7D%5D) + 8lw
 + 8lw
To minimize the cost of the sides 


 ---------(1)
 ---------(1)


 
 
 -------(2)
-------(2)
Now place the value of w from equation (1) to equation (2)


l³ = 378
l = ∛378 = 7.23 cm
From equation (2) 


w = 7.23 cm
As lwh = 504 cm³
(7.23)²h = 504

h = 9.64 cm                         
 
        
             
        
        
        
I would say the answer is b, because it is a rhombus gape and all sides are congruent and there are 4 sides
        
                    
             
        
        
        
But <span>160000000 can't be a decimal, because its whole number, unless its a percent, or a fraction.</span>
        
             
        
        
        
Answer:
The answer is A. 
Step-by-step explanation:
So we have the two equations: 

To make a substitution of the second equation into the first equation, we need to isolate the <em>y </em>variable in the second equation. Thus: 

Now, we can substitute this into the first equation. Therefore: 
