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Elena L [17]
3 years ago
8

A tumor originally weighed 34 g. Every day, chemotherapy treatment reduces the size of the tumor by 2.49 g. Express the size of

the tumor as a linear function of the number of days spent in chemotherapy then determine how much the tumor weighs after 5 days of treatment
Mathematics
1 answer:
Oxana [17]3 years ago
7 0

Initial mass: 34g

Daily reduction: 2.49g

The tumor mass, as function of days, is:

m(t)=34-2.49t, where t is time in days.

In the first day, t=0, mass is m(0)=34g. Next day, t=1, mass is m(1)=34-2.49.

After 5 days: m(5)=34-2.49×5=21.55g.

Answers: m(t)=34-2.49t

After 5 days: m(5)=21.55g

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Please help me thanks.
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y=(-2x)+5

Step-by-step explanation:

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Jared creates a number sequence that has a first term of 2 and a second of term of 5. Each term after the second is created by s
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The rule for the sequence is S(n) = 2S(n-1) - S(n-2)

Alternative form: S(n) = S(n-1) + 3

Step-by-step explanation:

In this problem, we know the first two terms of the sequence:

S(1) = 2

S(2) = 5

We are told that each term after the second is created by subtracting the term before the previous term from twice the previous term. In other words, if we call:

S(n) the current term

S(n-1) the previous term

S(n-2) the term before the previous term

This statement translates into the following sequence:

S(n) = 2S(n-1) - S(n-2)

Because we are subtracting the term before the previous term, S(n-2), from twice the previous term, 2S(n-1).

We can apply now the rule to find the first few terms of the sequence after S(1) and S(2):

S(3) = 2S(2) - S(1) = 2(5)-2=10-2 = 8

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We notice also that each term of the sequence is just equal to the previous term plus 3, so the sequence can also be written as

S(n) = S(n-1) + 3

Learn more about sequences:

brainly.com/question/1522572

brainly.com/question/3280369

#LearnwithBrainly

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