All categories

3 years ago

Help. and please show workout so I can know how to understand it (and both questions)

Mathematics

1 answer:

Arlecino [84]3 years ago

8 0

Just remove the parenthesis since you are adding them and combine like terms
x+5+2x+3
3x+8

You might be interested in

Which two movements will show a positive movement?

fiasKO [112]

Answer:
Right and up

3 0

3 years ago

Work out the interior angle of the octagon.<br> Please show the working out.

bija089 [108]

Answer:

135°

Step-by-step explanation:

formula = (n-2) * 180, whereby 'n' is the number of sides.

therefore, (8-2) * 180 = 1080°

1080° ÷ number of sides

= 1080° ÷ 8

= 135°

5 0

2 years ago

Read 2 more answers

Given m < TUV = 78, find m < WUV

meriva

Answer:

m∠WUV = 23°

Step-by-step explanation:

m∠TUW and m∠WUV must add up to m∠TUV

Step 1: Set up equation

m∠TUW + m∠WUV = m∠TUV

8x + 7 + 4x - 1 = 78

Step 2: Solve for <em>x</em>

12x + 6 = 78

12x = 72

x = 6

Step 3: Find m∠WUV

m∠WUV = 4x - 1

m∠WUV = 4(6) - 1

m∠WUV = 24 - 1

m∠WUV = 23°

7 0

3 years ago

Please answer correctly !!!!!!!!! Will<br> Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

6 0

3 years ago

Choose the similarity statement

Fofino [41]

Answer:

ΔMLN - ΔΡQO

Step-by-step explanation:

LMN change to MLN

OPQ change to PQO

Therefore,due to the correct pattern ΔMLN - ΔΡQO is correct.

3 0

3 years ago