Given: ABCD is a trapezoid, AC ⊥ CD , AB = CD, AC= square root of 75 , AB = 5 Find: Area of ABCD

1 answer:

8 0

Area of ABCD = 1/2(b1+b2) h
= 1/2(5+5) √75
= 5 √75
= 25√3

answer

Area = 25√3

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