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2 years ago

12

The four of you split the cost of materials you bought for your lemonade stand if the total cost was 85$ how much did you each p

ay? (Please I need help)

1 answer:

Mice21 [21]2 years ago

5 0

Just divide 85 by 4 and you get $21.25

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3 years ago

Solve the equation 2(x-4)=-22

Tcecarenko [31]

Hello Lexi!

<u><em>Answer: ⇒⇒⇒⇒⇒⇒ $x=-7$ </em></u>

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Step-by-step explanation:

First you had to divide by 2 from both sides of equation.

$\frac{2(x-4)}{2}=\frac{-22}{2}$

Simplify.

$\frac{2(x-4)}{2}=x-4$

$\frac{2(x-4)}{2}$

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$\frac{2}{2}=1$

$=x-4$

$\frac{-22}{2}=-11$

Apply the fraction rule.

$\frac{-22}{2}$

$=-\frac{22}{2}$

Then you divide by the number.

$\frac{22}{2}=11$

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$x-4=-11$

Add by 4 from both sides of equation.

$x-4+4=-11+4$

Simplify it should be the correct answer.

$x=-7$

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Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

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3 years ago

Read 2 more answers

( 8 x 10^-3 ) * (0.0002) = ?<br><br> In scientific notation please

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1.6 × 10 to the negative sixth power "10 -6".

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3 years ago

Suppose that a recent article stated that the mean time spent in jail by a first-time convicted burglar is 2.5 years. A study wa

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Using the z-distribution, it is found that since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

At the null hypothesis, it is <u>tested if the mean length of jail time is still of 2.5 years</u>, that is:

$H_0: \mu = 2.5$

At the alternative hypothesis, it is <u>tested if it has increased</u>, that is:

$H_1: \mu > 2.5$

We have the <u>standard deviation for the population</u>, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.
$\mu$ is the value tested at the null hypothesis.
$\sigma$ is the standard deviation of the sample.
n is the sample size.

For this problem, the values of the <u>parameters</u> are: $\overline{x} = 3, \mu = 2.5, \sigma = 1.5, n = 26$

Hence, the value of the <u>test statistic</u> is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{3 - 2.5}{\frac{1.5}{\sqrt{26}}}$

$z = 1.7$

The critical value for a <u>right-tailed test</u>, as we are testing if the mean is greater than a value, with a <u>significance level of 0.05</u>, is of $z^{\ast} = 1.645$

Since the <u>test statistic is greater than the critical value</u>, it can be concluded that the mean length of jail time has increased.

A similar problem is given at brainly.com/question/24166849

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2 years ago