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fredd [130]
3 years ago
7

Five-thirds divided by one-third =

Mathematics
2 answers:
vova2212 [387]3 years ago
8 0

Answer:

Step-by-step explanation: \frac{5}{3}÷\frac{1}{3} =

(Decimal: 0.555556)

Kruka [31]3 years ago
6 0

Answer:

0.5

Step-by-step explanation:

which equals a half in a fraction

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SVETLANKA909090 [29]
-3+-6=-9 -9 is how many yards the football team has lost overall in the two plays
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3 years ago
Linda needs 20 gallons of juice that has 75%fruit juice. she has a mixture that has 80% fruit juice and another mixtures that ha
suter [353]
Linda should use ...
  15 gallons of 80% juice
  5 gallons of 60% juice

_____
Let g represent the number of gallons of 80% juice needed. Then (20-g) is the number of gallons of 60% juice Linda will use. The amount of juice in the mixture can be written as
  0.80g +0.60(20 -g) = 0.75×20
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The amount of 80% juice needed is 15 gallons, so 5 gallons of 60% juice are needed.
5 0
3 years ago
How would you graph 10<=20
irinina [24]

Answer:

with a line

Step-by-step explanation:

so you get a use a graph calculator and you put in that and it shows the answer.

8 0
4 years ago
Read 2 more answers
Please help with this!!! 25 points and i'll mark you brainliest!!! Show how you got answer!!!
HACTEHA [7]

Answer:

17.9°

Step-by-step explanation:

From trigonometry:

Opposite = 14

Adjacent = x

theta = 38°

hence;

tan theta = opposite/ adjacent

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x = 14/tan38°

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6 0
3 years ago
Use Newton's method with initial approximation x1 = 1 to find x2, the second approximation to the root of the equation x4 − x −
drek231 [11]

Answer:

x_{2} = 0.0000

Step-by-step explanation:

The formula for the Newton's method is:

x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}

Where f' (x_{i}) is the first derivative of the function evaluated in x_{i}.

x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}

Lastly, the value of x_{2} is determined by replacing x_{1} with its numerical value:

x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}

x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}

x_{2} = 0.0000

8 0
3 years ago
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