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ra1l [238]
3 years ago
11

What's 7n-4=31? What's n=??

Mathematics
2 answers:
levacccp [35]3 years ago
7 0

Answer:

5

Step-by-step explanation:

solve for n. subtract 4 from 31 and you get 35 then divide 7 by 35 in order to get n which is 5.

sveticcg [70]3 years ago
4 0

Answer:

n=5

Step-by-step explanation:

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Abdul buys dress pants from a clothing company for p dollars. He then sells each pair of pants in his men’s clothing shop at a 4
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Answer:the last one

Step-by-step explanation:

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2 years ago
Pam runs 50 meters in 12 seconds, how far can she run in 7 seconds?
podryga [215]

Answer: 30 meters

Step-by-step explanation:

50/12=4.1666

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5 0
2 years ago
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ANSWER FAST ITS URGENT
Vlad1618 [11]

Answer:

9) 6.3 units

11) n=6√2 and m=12,

10) m=6√3, n=6

12) 330.6 ft

Step-by-step explanation:

1) The Pythagoras Theorem says that, the square of the hypotenuse is the sum of the squares of the two shorter legs.

Let the missing side, which is the hypotenuse be x.

Then

{x}^{2}  =  {2}^{2}  +  {6}^{2}

{x}^{2}  = 4 + 36

{x}^{2}  = 40

x =  \sqrt{40}

x = 6.3

The missing side is 6.3 units to the nearest tenth.

2) This is an isosceles right triangle.

This implies that, the two legs are equal.

n = 6 \sqrt{2}

The hypotenuse can be found using Pythagoras Theorem.

{m}^{2}  =  {(6 \sqrt{2} )}^{2}  +  {(6 \sqrt{2} )}^{2}

{m}^{2}  = 36(4)

m =  \sqrt{36 \times 4}  = 6 \times 2 = 12

3) The side lengths of 30°-60°-90° are in the ratio, 2x,x√3,x

From the diagram, the hypotenuse is 12, therefore the other two legs are

n =  \frac{1}{2} (12) = 6

and

m = 6 \sqrt{3}

4) The height of the monument is 115 feet, the hypotenuse is 350.

By Pythagoras Theorem,

{x}^{2}  +  {115}^{2}  =  {350}^{2}

{x}^{2}  =  {350}^{2}   -  {115}^{2}

{x}^{2}  = 109275

x =  \sqrt{109275}  = 330.6 ft

3 0
3 years ago
Graph of Parent Functions
Tanya [424]

Answer:

A parent function is the simplest function of a family of functions. of this form is y = x2. The simplest parabola is y = x2, whose graph is shown at the right. The graph passes through the origin (0,0), and is contained in Quadrants I and II.

Hope it helped u if yes mark me BRAINLIEST pzllzllzl plzz plzzz

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6 0
3 years ago
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Please help!!!!!!!!!!!!!!!! 100pts,
Helga [31]

QUESTION:

The code for a lock consists of 5 digits (0-9). The last number cannot be 0 or 1. How many different codes are possible.

ANSWER:

Since in this particular scenario, the order of the numbers matter, we can use the Permutation Formula:–

  • P(n,r) = n!/(n−r)! where n is the number of numbers in the set and r is the subset.

Since there are 10 digits to choose from, we can assume that n = 10.

Similarly, since there are 5 numbers that need to be chosen out of the ten, we can assume that r = 5.

Now, plug these values into the formula and solve:

= 10!(10−5)!

= 10!5!

= 10⋅9⋅8⋅7⋅6

= 30240.

3 0
2 years ago
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