All categories

3 years ago

Let's say you have two similar polygons and the ratio of their perimeters is 6:1. What is the ratio of corresponding sides?

1 answer:

7 0

Well if we had a four sided polygon with the sides of x1, x2, x3, x4. Where the perimeter is: (x1 + x2 + x3 + x4), A similar polygon will have proportional sides. Their sides would be > kx1, kx2, kx3, kx4.....sooo... The perimeter is: (kx1 + kx2 + kx3 + kx4) > k(x1 + x2 + x3 + x4) therefore the ratio is the same because the perimeter and sides are the same. So 6:1

Hope this helps!

You might be interested in

You earned $75.70. You would like to buy some new T-shirts. Estimate the number of T-shirts you can buy if each one costs $10.80

Alex787 [66]

the answer is 7 t-shirts

divide 75.70 by 10.80

hope this helped :)

4 0

3 years ago

Find the measures of an interior angle and an exterior angle of a regular hexagon. The measure of an interior angle is 120. The

Tom [10]

Answer:

see explanation

Step-by-step explanation:

Since a hexagon has 6 interior angles and the measure of one is 120°, then

sum of interior angles = 6 × 120° = 720°

exterior angle = 180° - interior angle = 180° - 120° = 60°

7 0

2 years ago

Can you please answer

BabaBlast [244]

I believe it should be A.

7 0

2 years ago

Helppp can someone solve this please

Norma-Jean [14]

Answer:

$\displaystyle x=-15$

Step-by-step explanation:

<u>Solution Of A System Of Equations </u>

A system of linear equations is given as

$\displaystyle \left\{\begin{matrix}ax+by=c\\ dx+ey=f\end{matrix}\right.$

There are many methods to solve them. We will use the method of reduction

The given system is

$\displaystyle \left\{\begin{matrix}2x+3y=45\\ x+y=10\end{matrix}\right.$

Multiplying the second equation by -3

$\displaystyle \left\{\begin{matrix}2x+3y=45\\ -3x-3y=-30\end{matrix}\right.$

Adding the resulting equations

$\displaystyle -x=15$

$\displaystyle x=-15$

5 0

2 years ago

Find the perimeter of quadrilateral PQRS with the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3).

storchak [24]

Answer:

$P=16.53\ units$

Step-by-step explanation:

we know that

The perimeter of quadrilateral PQRS is equal to the sum of its four length sides

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

the vertices P(2,4), Q(2,3), R(-2,-2), and S(-2,3)

step 1

Find the distance PQ

P(2,4), Q(2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(0)^{2}}$

$d=\sqrt{1}$

$dPQ=1\ unit$

step 2

Find the distance QR

Q(2,3), R(-2,-2)

substitute in the formula

$d=\sqrt{(-2-3)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-5)^{2}+(-4)^{2}}$

$dQR=\sqrt{41}\ units$

step 3

Find the distance RS

R(-2,-2), and S(-2,3)

substitute in the formula

$d=\sqrt{(3+2)^{2}+(-2+2)^{2}}$

$d=\sqrt{(5)^{2}+(0)^{2}}$

$dRS=5\ units$

step 4

Find the distance PS

P(2,4), S(-2,3)

substitute in the formula

$d=\sqrt{(3-4)^{2}+(-2-2)^{2}}$

$d=\sqrt{(-1)^{2}+(-4)^{2}}$

$dPS=\sqrt{17}\ units$

step 5

Find the perimeter

$P=PQ+QR+RS+PS$

substitute the values

$P=1+\sqrt{41}+5+\sqrt{17}$

$P=6+\sqrt{41}+\sqrt{17}$

$P=16.53\ units$

5 0

3 years ago