Answer:
NO DO YOU'RE HW
Step-by-step explanation:
Answer:
0
Step-by-step explanation:
substitute 1 for v
2(1)^3 - 1^2 + 3(1) - 4
2 - 1 + 3 - 4
1 + -1
0
Answer: The cumulative frequency of club members who exercise publicly for six or fewer times per week = 38
Step-by-step explanation:
The given results of the survey:
0 visits per week: 13
1-3 visits per week: 17
4-6 visits per week: 8
7 or more visits per week: 17
The cumulative frequency of club members who exercise publicly for six or fewer times per week = Frequency for 0 visits + Frequency for 1-3 visits per week + Frequency for 4-6 visits per week
= 13+17+8
=38
Hence, the cumulative frequency of club members who exercise publicly for six or fewer times per week = 38
Answer:
It's 3/2p!
Step-by-step explanation:
Because Helen do the same number of exercises on 2 days, the time to do and the average rate are inversely proportional!
So, if on Monday, Helen's average rate is p then on the next day, her average rate is:
p × 3 ÷ 2 =
=3/2p
Brainliest?
Answer:
The answer to your question is:
a) P(3) = 5818 mosquitoes
b) 4 days
Step-by-step explanation:
Data
P(t) = Poekt
a)
Po = 1000 mosquitoes
Pt = 1800
t = 1 day
P(3) = ?
1800 = 1000 e1k
1800 / 1000 = e 1k
e 1k = 1.8
1k = In 1.8
k = 0.587
P(3) = 1000 e (0.587)(3)
P (3) = 1000 e 1.761
P(3) = 5818. 2 mosquitoes
b)
P(t) = 10,000
10000 = 1000 e 0.587t
10000 / 1000 = e 0.587t
10 = e 0.587t
In 10 = in e 0.587t
2.3 = 0.587t
t = 3.92 days ≈ 4 days