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2 years ago

a father is twice as old as his son. 20 yrs ago the father was four times as old as his son. find their present ages

Mathematics

1 answer:

Roman55 [17]2 years ago

5 0

Answer:

son's present age = 30

father's present age=60

Step-by-step explanation:

his son's present age = x years

his father's present age = 2x years

before 20 years his son's age=(x-20) years

before 20 years father's age=(2x-20) years4(x-20)=(2x-20)

4x-80=2x-20

4x-2x=80-20

2x=60

x=30

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