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miskamm [114]
2 years ago
9

a father is twice as old as his son. 20 yrs ago the father was four times as old as his son. find their present ages

Mathematics
1 answer:
Roman55 [17]2 years ago
5 0

Answer:

son's present age = 30

father's present age=60

Step-by-step explanation:

his son's present age = x years

his father's present age = 2x years

before 20 years his son's age=(x-20) years

before 20 years father's age=(2x-20) years4(x-20)=(2x-20)

4x-80=2x-20

4x-2x=80-20

2x=60

x=30

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Parallelogram PQRS is shown. m/S=(3x), m/R=120, and m/Q=(2y). Find the value of y.A.
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Option B. From the parallelogram PQRS the value of y is given to be 30

<h3>How to solve for the value of y from the parallelogram</h3>

In order to get the value of y we have to use the formula

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