Answer:
The mean score in the math test for class B=28.47
Step-by-step explanation:
<em>Step 1: Determine the total number of students in both Classes</em>
Total number of students=number in class A+number in class B
where;
number in class A=11 pupils
number in class B=15 pupils
replacing;
Total number of students=11+15=26 students
<em>Step 2: Determine total score for both classes</em>
Total score for both classes=total score for class A+total score for class B
total score for both classes=mean score for both classes×total number of students
total score for both classes=(49×26)=1,274
total score for class A=mean score for class A×total number of class A students
total score for class A=(77×11)=847
total score for class B=mean score for class B×total number of class B students
total score for class B=m×15=15 m
replacing;
1,274=847+15 m
15 m=1,274-847
15 m=427
m=427/15=28.47
The mean score in the math test for class B=28.47
The answer is 3.9. In fraction form the answer is 89/10. In mixed fraction form the answer is 8 9/10
Answer:
C
Step-by-step explanation:
the definition of an irrational number is an infinite decimal that has no repeating pattern. rational numbers can be converted into fractions.
A is incorrect because a whole number can be converted into a fraction.
ex: 1 is also 3/3
B is incorrect because the definition of a rational number is that it can be converted into a fraction.
D is incorrect because a terminating decimal can be made into a fraction.
ex: 4.5 is also 9/2
Answer and Step-by-step explanation: The <u>critical</u> <u>value</u> for a desired confidence level is the distance where you must go above and below the center of distribution to obtain an area of the desired level.
Each sample has a different degree of freedom and critical value.
To determine critical value:
1) Calculate degree of freedom: df = n - 1
2) Subtract the level per 100%;
3) Divide the result by 2 tails;
4) Use calculator or table to find the critical value t*;
For n = 5 Level = 90%:
df = 4
t = = 0.05
Using t-table:
t* = 2.132
n = 13 Level = 95%:
df = 12
t = = 0.025
Then:
t* = 2.160
n = 22 Level = 98%
df = 21
t = = 0.01
t* = 2.819
n = 15 Level = 99%
df = 14
t = = 0.005
t* = 2.977
The critical values and degree of freedom are:
sample size level df critical value
5 90% 4 2.132
13 95% 12 2.160
22 98% 21 2.819
15 99% 14 2.977