We define the probability of a particular event occurring as:

What are the total number of possible outcomes for the rolling of two dice? The rolls - though performed at the same time - are <em>independent</em>, which means one roll has no effect on the other. There are six possible outcomes for the first die, and for <em>each </em>of those, there are six possible outcomes for the second, for a total of 6 x 6 = 36 possible rolls.
Now that we've found the number of possible outcomes, we need to find the number of <em>desired</em> outcomes. What are our desired outcomes in this problem? They are asking for all outcomes where there is <em>at least one 5 rolled</em>. It turns out, there are only 3:
(1) D1 - 5, D2 - Anything else, (2), D1 - Anything else, D2 - 5, and (3) D1 - 5, D2 - 5
So, we have

probability of rolling at least one 5.
Answer:
I think 4/7 but i'm not sure.
Step-by-step explanation:
Answer:
Step-by-step explanation:
3y+5y=8y
8y=7(divide 8 in both sides to get y)
y=7/8
x+2y=3...but we already know the value of y, so substitute 7/8 to y
x+2(7/8)=3
x+14/8=3
x=3-14/8
=1.25
Answer:
<u>C) −12/5⋅(7/12⋅1/9)⋅8/5=(−12/5⋅7/12)⋅(1/9⋅8/5)</u>