A) 6u+3u+4-15= (9u-11) <---answer ;) B)-1-2u-9-(-5u)=(3u-10)<--answer C) 7u+25+(-10u)-16= (-3u+9)<--answeeer
Make an equation system based on the problem
eg. a is the first number and b is the seond number
An equation for "<span>The sum of two numbers is 53" is
</span>⇒ a + b = 53
An equation for "<span>twice the first number minus three times the second number is 26"
</span>⇒ 2a - 3b = 26
<span>
Solve the equations by elimination and subtitution method
Eliminate a to find the value of b
a + b = 53 (multiplied by 2)
2a - 3b = 26
--------------------------------------
2a + 2b = 106
2a - 3b = 26
------------------- - (substract)
5b = 80
b = 80/5
b = 16
Subtitute the value of b to one of the equations
a + b = 53
a + 16 = 53
a = 53 - 16
a = 37
The numbers are 16 and 37</span>
Answer:
B?
Step-by-step explanation:
Answer:
b. y = -7x + 4
1. y = -7(-5)+ 4 = 35+4= 39
2. -24= -7x + 4
-28 = -7x
4 = x
3. y = -7(0)+4= 4
4. 0 = -7x+4
-4= -7x
4/7 = x
c. 3y - 5x = 15
1. 3y - 5(6)
3y-30=15
3y=45
y = 15
2. 3(-10)-5x=15
-30-5x=15
-5x = 45
x = -9
3. 3y-5(0)=15
3y=15
y=5
4. 3(0)-5x=15
0-5x=15
-5x=15
x=-3
Step-by-step explanation:
This isn't even math and there all wrong
