Answer:
Step-by-step explanation: This is the quadratic function:
h(x)=ax²+bx+c
We have two points:
(1,58)
(2,112)
Now, we calculate this quadratic funtion.
we assume that h(0)=0
Therefore:
a(0)²+b(0)+c=0
c=0
(1,58)
a(1)²+b(1)=58
a+b=58 (1)
(2,112)
a(2)²+b(2)=112
4a+2b=112
2a+b=56 (1)
With the equations (1) and (2) we make a system of equations:
a+b=58
2a+b=56
we can solve this system of equations by reduction method.
-(a+b=58)
2a+b=56
---------------------
a=-2
-2(a+b=58)
2a+b=56
-------------------
-b=-60 ⇒ b=60
The function is:
h(x)=ax²+bx+c
h(x)=-2x²+60x
Now find the height, in feet, of the rock after 10 seconds in the air.
h(10)=-2(10)²+60(10)
h(10)=-200+600=400
Answer: 400 ft.
Answer:
C. 2.8 * 10^-5
Step-by-step explanation:
Ok so its been a while since I've done these but pretty sure c is the answer. (Double check to make sure I'm correct)
Answer: 24 fliers
Step-by-step explanation:
he had 80 to begin with so last week if he posted 1/4 of them he would have 3/4 left and
3/4 * 80 = 60
and then if he posts 3/5 of the 60 remaining fliers he would have 2/5 left over and
2/5 * 60 = 24
so your answer is 24 fliers
well, you saw it on the previous exercise, 8.25 x 10⁻⁶, it <u>looks</u> like 8.25 is some value between 1 and 10, but is not really, the 10⁻⁶ is disguising that is really much smaller than that, in fact much smaller than even 1.
