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QveST [7]
3 years ago
13

Factor the expression gcf 12w-18

Mathematics
2 answers:
zloy xaker [14]3 years ago
7 0

factor 12w -18

   12w -18  what goes into 12w and -18?  lets go with 2

2  (6w - 9)  can 6w and -9 be factored more?  yes by 3

2 x 3 (2w -3)

so

6 (2w -3)

prohojiy [21]3 years ago
4 0

12w = 6 · 2w

18 = 6 · 3

12w - 18 = 6 · 2w - 6 · 3 = 6(2w - 3)

<h3>Answer: 12w - 18 = 6(2w - 3)</h3>
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Answer:

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Step-by-step explanation:

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second point (18,17)

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m=(17-1)/(18-14)

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2 years ago
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3 0
2 years ago
Heron wants to buy a video game. The price is regularly priced at 55 dollars. The store has a discount of 20% off and a sales ta
nadezda [96]

The amount paid by Heron for the video game  is $46.64.

Step-by-step explanation:

Here, the marked price of the video game  = $55

The discount percentage on the video game  = 20%

Calculating 20% of the $55, we get:

\frac{20}{100}  \times 55  = 11

So, the discount offered on the video game  = $11

Selling Price  = Marked Price  - Discount

                        =$55 - $11 = $44

Now,  the tax percentage on the video game  = 6%

Calculating 6% of the $44, we get:

\frac{6}{100}  \times 44  =2.64

So, the tax  on the video game  = $2.64

New Selling Price  = Selling Price  +  Tax

                        =$44 + $2.64  = $46.64

So, the amount paid by Heron for the video game  is $46.64.

4 0
2 years ago
A man weighing 800 N is hanging from a 2 mm diameter titanium wire with a cross-section of 3 x 10^-6 m^2. Will the wire break?
DENIUS [597]

Answer:

Since stress is greater than ultimate strength, the wire will break.

Step-by-step explanation:

The titanium wire is experimenting an axial load. Ultimate strength equals 2.20\times 10^{8}\,Pa. The wire shall break if and only if stress is at least equal to ultimate strength. The equation for axial stress (\sigma), measured in pascals, in the wire with circular cross-section is:

\sigma = \frac{4\cdot F}{\pi\cdot D^{2}} (1)

Where:

F - Axial force, measured in newtons.

D - Cross-section diameter, measured in meters.

Please notice that axial force is the weight of the man hanging from wire.

If we know that F = 800\,N and D = 0.002\,m, then the axial stress experimented by the titanium wire is:

\sigma = \frac{4\cdot (800\,N)}{\pi\cdot (0.002\,m)^{2}}

\sigma \approx 2.546\times 10^{8}\,Pa

Since stress is greater than ultimate strength, the wire will break.

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2 years ago
Find the sum of 10 + 5i and its complex conjugate.
ra1l [238]

Answer:

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Given, complex number is 10+5i .

We need to find sum of the given complex number and its conjugate. The conjugate of 10+5i is 10-5i. Therefore, the sum will be 10+5i+10−5i=20.

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