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yan [13]
4 years ago
14

What is the value of x?

Mathematics
1 answer:
cricket20 [7]4 years ago
8 0
180-93.5=86.5
x=86.5:2=43.25
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Here, thankyou!!!!!!!
FromTheMoon [43]

Answer:

Perimeter of i - 22CM

Area of i - 13CM^2

Perimeter of ii -38CM

Area of ii -66CM^2

Perimeter of iii -30CM

Area of iii- 42CM^2

Perimeter of iv - 50CM

Area of iv- 126CM^2

Step-by-step explanation:

SHAPE I:

PERIMETER = S + S + S + S + S +S

= 7 + 1 + 5 +3 +4 +2

= 22CM

AREA = Part a - 4 * 2 = 8cm^2 part B - 5 *1 = 5cm^2

Total = 8 + 5 = 13cm^2

SHAPE II:

PERIMETER = S + S + S + S + S +S

= 4 + 4 +5 + 6 + 9 + 10

= 38 CM

AREA = Part a - 5 * 10 = 50 cm^2 part B - 4 *4 =16 cm^2

Total = 50+16 =66 cm^2

SHAPE III:

PERIMETER = S + S + S + S + S +S

= 9 + 2 + 3 + 4 + 6 + 6

= 30CM

AREA = Part a - 6 * 6 = 42cm^2 part B - 3 * 2= 6cm^2

Total = 36 + 6 =42 cm^2

SHAPE IV:

PERIMETER = S + S + S + S + S +S

= 9 + 10 + 4 + 6 + 6 + 15

= 50 CM

AREA = Part a -15 * 6 = 90 cm^2 part B - 9 *4 = 36cm^2

Total = 90 + 36 = 126cm^2

HOPE THIS HELPED

6 0
3 years ago
A house rental costs $150 per night. The rental company
zvonat [6]
The answer is A. 150x + 50.
3 0
3 years ago
Two ropes, AD and BD, are tied to a peg on the ground at point D. The other ends of the ropes are tied to points A and B on a fl
Salsk061 [2.6K]
So to find the answer you need to use SOHCAHTOA 
Sine= Opposite/ Adjacent
Cosine= Adjacent/Hypotenuse
Tan = opposite/adjacent

angle ADC is 60 so to find the length of line ABC we would use the angle and the line DC. 
We would use Tan with opposite over adjacent
Tan 60 = opp. / 5 root 3 
opp. = 15 
so that is the length of the entire thing, all you need to do now is find the length of the single line of BC which we can use the same equation with just Tan 30 now.
Tan 30 = opp. / 5 root 3 
opp. = 5 
next you need to take the entire ABC length and subtract the length of BC to get AB
15-5 = 10 
so the answer would be C
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Ctt%286x4%E2%88%922x3%20%2B7x2%20%E2%88%92x%29%20%2B%20%28%207x4%2B%202x3%E2%88%925x%20%2
Vadim26 [7]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's solve ~

\qquad \tt \dashrightarrow \:\tt(6x {}^{4} −2x {}^{3}  +7x {}^{2} −x) + ( 7x {}^{4} + 2x {}^{3} −5x + 7)

\qquad \tt \dashrightarrow \:\tt6x {}^{4} −2x {}^{3}  +7x {}^{2} −x +  7x {}^{4} + 2x {}^{3} −5x + 7

Now, move all like terms aside :

\qquad \tt \dashrightarrow \:6 {x}^{4}  + 7 {}x^{4}  - 2 {x}^{3}  + 2 {x}^{3}  + 7 {x}^{2}  - x - 5x + 7

Add the like terms ~

\qquad \tt \dashrightarrow \:13 {}x^{4}   + 7 {x}^{2}   + 6x + 7

3 0
2 years ago
Read 2 more answers
In a group of 23 students, 2 study both Art and Biology.
Iteru [2.4K]

Answer:

azzzzz

Step-by-step explanation:

6 0
3 years ago
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