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mario62 [17]
3 years ago
12

Which letters have more than one line of symmetry?

Mathematics
2 answers:
OLga [1]3 years ago
4 0
O, X and H have more than one line of symmetry.

Hope I helped you!
Ⓞⓢⓢⓐⓢⓗⓘ  ╰☆╮<span> ╰☆╮</span>




klemol [59]3 years ago
3 0
The letter 'C' has 2 lines of symmerty
the upper-case 'D' has 2 lines of symmetry
the uper -case 'E' has 2 lines of symmetry
the upper case 'H' has 2 lines of symmetry
the upper case 'I' has 2 lines of symmetry
the small case 'L' has 2 lines of symmmetry
the letter 'O' has infinite lines of symetry
the letter 'x' has 4 lines of symmetry



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Solve for "x" : 2x + 3x + 4x =36​
Anestetic [448]

Answer:

4

Step-by-step explanation:

2x + 3x + 4x = 36

Evaluate like terms.

9x = 36

Find x.

x = 36 ÷ 9

x = 4

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3 years ago
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A student receives test scores of 62, 83, and 91. This student's term project score is 88. Each test is worth 20% of the final g
miskamm [114]

Answer:

The student's current average score will be 69.2

Step-by-step explanation:

Let first test be TEST A: which is 20 of total and secures 62

Let second test be TEST B: which is 20 of the total marks and has secured 83.

Let third test be TEST C: which is 20 of total and has secured 91.

And now the TEST D which is 25 of total and has secured 88.

Therefore, by multipying across

{0.2}\times{62} = 12.4

{0.2}\times{83} = 16.6

{0.2}\times{91} = 18.2

{0.25}\times{88} =22

Now, by adding the scores to get the average score

We get, 69.2.

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2 years ago
Nathan brought a pair of boots for $80 and 1 shirt for $20. the sales tax is 5%. how much did Nathan pay for all the items inclu
Paladinen [302]
He paid 103$ hope it helps
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2 years ago
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Noa hopes to pick the winning ticket during her math class’s raffle. the student who picks the ticket with a true statement will
Natali5045456 [20]

Answer: The winning ticket is 2(x-6)=-35 is equivalent to 2x=-23.



Step-by-step explanation:

Let's check all the options

4(x-5)=35 is not equivalent to 4x=40

\text{since }4(x-5)=35\\\Rightarrow4x-20=35\\\Rightarrow4x=35+20\\\Rightarrow4x=55

8(x-7)=35 is not equivalent to 8x=28


\text{since }8(x-7)=35\\\Rightarrow8x-56=35\\\Rightarrow8x=35+56\\\Rightarrow8x=91

2(x-6)=-35 is equivalent to 2x=-23


\text{since }2(x-6)=-35\\\Rightarrow2x-12=-35\\\Rightarrow2x=-35+12\\\Rightarrow2x=-23

9(x-6)=-35 is not equivalent to 9x=-29

\text{since }9(x-5)=-35\\\Rightarrow9x--40=-35\\\Rightarrow9x=-35+40\\\Rightarrow9x=5

Thus, the winning ticket is 2(x-6)=-35 is equivalent to 2x=-23.

4 0
2 years ago
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Garne Problem med
Citrus2011 [14]

Total distance the rover need to travel ​is D = 1miles .

<u>Step-by-step explanation:</u>

We have , Garne Problem med   . A rover needs to travel mile to reach its destination  traveled mile. a rover needs to travel 5/8 mile to reach its destination it has already travel 3/8 miles . We need to find that  how much farther does the rover need to travel ​ , Let's do it step by step:

First , rover has already traveled 3/8 miles , Let total distance to be traveled by rover is D :

⇒ D = \frac{3}{8} + d , where d is distance left to cover .

Now, rover need to travel 5/8 miles more to reach destination :

⇒ D = \frac{3}{8} + d , where d is distance left to cover  , So d = \frac{5}{8}

⇒ D = \frac{3}{8} + d

⇒ D = \frac{3}{8} + \frac{5}{8}

⇒ D = \frac{3+5}{8}

⇒ D = \frac{8}{8}

⇒ D = 1miles

∴ Total distance the rover need to travel ​is D = 1miles .

8 0
3 years ago
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