Reflect triangle A in the line y = 1.
1 answer:
Answer:
Step-by-step explanation:
In the figure attached,
Vertices of the triangle ABC are A(-4, 4), B(-1, 4) and (-1, 2)
When we reflect this figure across a line y = 1
Vertices of the image triangle A'B'C' will be
Coordinates of A'
A(-4, 4) → A'[(1 + 5), 4]
→ A'(6, 4)
Coordinates of B'
B(-1, 4) → B'(-1 + 4, 4)
→ B'(3, 4)
Coordinates of C',
C(-1, 2) → C'[(-1 + 4), 2]
→ C'(3, 2)
Graph these points and join them to form the image triangle A'B'C'.
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Answer:
The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
Step-by-step explanation:
Let be , where
is the stopping distance measured in metres and
is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.
The procedure to find the speed related to the given stopping distance is described below:
1) Construct the graph of .
2) Add the function .
3) The point of intersection between both curves contains the speed related to given stopping distance.
In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.
