If the speed of light in a vacuum is twice that of the speed of light in a given material, what is the index of infraction for t
hat material?
2 answers:
I halved the speed of light in vacuum to get the speed of light in the material, since the speed of light in vacuum is twice the speed of light in material.
The index of refraction is essentially the speed of light through a vacuum divided by the speed of light through given medium.
I attached some notes on refraction too, hopefully this helps :D
The index of refraction is essentially the speed of light through a vacuum divided by the speed of light through given medium.
I attached some notes on refraction too, hopefully this helps :D
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Answer:
4.4345× 10^-7V
Explanation:
The computation of the half voltage for a 1.2T magnetic field applied is shown below
The volume of one mole of copper is
v = m ÷p
= 63.5 ÷ 8.92
= 7.12cm
Now the density of free electrons in copper is
n = Na ÷ V
= 6.02 × 10^23 ÷ 7.12
= 8.456× 10^28/m^3
Now the half voltage is
= IB ÷ nqt
= (5 × 1.20) ÷ (8.456× 10^28 × 1.6 × 10^-19 × 0.1× 10^-2)
= 4.4345× 10^-7V
