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melamori03 [73]
3 years ago
7

Help please due by 3:00

Physics
1 answer:
FrozenT [24]3 years ago
8 0

Answer:

  zero

Explanation:

Acceleration is a measure of the rate of change of velocity. If the velocity is unchanging, its rate of change is zero.

The acceleration is zero.

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A 1800 kg car is accelerated at 2.6m/s^2 what force was needed to produce this acceleration
nataly862011 [7]

Answer:

4680 N

Explanation:

Force =mass x acceleration

Mass =1800kg

Acceleration =2.6m/s ^2

Hence Force = 1800kg x 2.6m/s

= 4680N

7 0
3 years ago
What is the restoring force of a spring with a spring constant of 4a and a stretched displacement of 3b? A. –7 ab B. `-7 a/b ` C
algol13

Answer:

C. -12 ab

Explanation:

The restoring force on a spring is given by Hooke's law:

F=-kx

where

k is the spring constant

x is the stretched (or compressed) displacement of the spring

In this problem we have:

k = 4a

x = 3b

Substituting into the equation, we find:

F=-(4a)(3b) = -12 ab

And the negative sign means that the direction of the force (negative) is opposite to the direction of the displacement (positive).

3 0
3 years ago
The earth’s magnetic field is located in the _____.
Natali [406]
Near Greenland in the northern hemisphere  <span />
7 0
3 years ago
The velocity of an object is equal to the distance divided by time. The equation is velocity = distance/time. If you wanted to c
Korolek [52]

Answer: C) divide: distance ÷ velocity

Explanation:

The velocity V equation is distance d divided by time t:

V=\frac{d}{t}

If we isolate t we will have:

t=\frac{d}{V}

Hence, the correct option is C: distance divided by velocity.

7 0
3 years ago
If a body travels half its total path in the last 1.50 s of its fall from rest, find the total time of its fall (in seconds).
svetoff [14.1K]

Answer:

time to fall is 3.914 seconds

Explanation:

given data

half distance time = 1.50 s

to find out

find the total time of its fall

solution

we consider here s is total distance

so equation of motion for distance

s = ut + 0.5 × at²   .........1

here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time

so for last 1.5 sec distance is 0.5 of its distance so equation will be

0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)²     ........................1

and

velocity will be

v = u + at

so velocity v = 0+ 9.8(t-1.5)    ..................2

so first we find time

0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5)  + 0.5 ( 9.8)

solve and we get t

t = 3.37 s

so time to fall is 3.914 seconds

6 0
4 years ago
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