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Stells [14]
3 years ago
6

Please help thank you!

Physics
2 answers:
liq [111]3 years ago
8 0

Answer:

I think d

Explanation:

because distance j

has to be the last one that's the only one with distance

larisa [96]3 years ago
6 0

Answer:

mass, weight

Explanation:

mass is constant, and weight is dependant on your location

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A 73-kg boy is surfing and catches a wave which gives him an initial speed of 1.6 m/s. He then drops through a height of 1.60 m,
Gnesinka [82]

To solve this problem it is necessary to apply the concepts related to the Conservation of Energy, for which it is necessary that any decrease made through the potential energy, is equivalent to the gain given in the kinetic energy or vice versa.

Mathematically this can be expressed as

KE_i+PE_i = KE_f+PE_f

Since there is no final potential energy (the height is zero), and the initial potential energy is equivalent to the work done we have to

W = KE_f-KE_i-PE_i

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W =\frac{1}{2} m(v_f^2-v_i^2)-mgh

W= \frac{1}{2}(73)(8.5^2-1.6^2)-(73*9.8*1.6)

W= 1399.045J

W= 1.4kJ

Therefore the non-conservative work was done on the boy is 1.4kJ

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Which best explains why the diagram shows refraction but not reflection?
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6 0
3 years ago
A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the
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Answer:

d = 120 [m]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.

The mechanical energy is equal to the sum of the potential energy plus the kinetic energy.  As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁  = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂  = mechanical energy in the final state = 0

E₁ = Ek = kinetic energy [J]

E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

where:

f = friction force = 36 [N]

d = distance [m]

Now we have:

0.5*m*v² - (f*d) = 0

0.5*60*(12)² - (36*d) = 0

4320 = 36*d

d = 120 [m]

7 0
2 years ago
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