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ElenaW [278]
3 years ago
10

Two quantities, x and y, are directly proportional. If you take a third of x, what happens to y

Mathematics
2 answers:
Law Incorporation [45]3 years ago
7 0
Answer: Because of the direct proportion, the y-value would also be one-third of what it was before. 
3241004551 [841]3 years ago
5 0
If two quantities are directly proportional, they increase and decrease at the same rate. Therefore, if you take a third of x, you also take a third of y.
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The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator
WARRIOR [948]

Answer: 5n = 3d and 3n + 6 = 2d + 4

Given that the numerator and denominator of a fraction are in the ratio of 3 to 5. When the numerator and denominator are both increased by 2, the fraction is equal to \dfrac{2}{3}.  

We are to select the system of equations that could be used to solve the problem.  

Since n denotes the numerator and m denotes the denominator of the given fraction, so we have:

n/d = 3/5

5n = 3d

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(n+2)/(d+2) = 2/3

3(n+2) = 2(d+2)

3n + 6 = 2d + 4

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5n = 3d and 3n + 6 = 2d + 4

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3 0
2 years ago
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
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