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ioda
3 years ago
13

Which of the following polynomials is the correct simplified form of -21x2+22x2-13x2-10x+5x-102?

Mathematics
1 answer:
gladu [14]3 years ago
4 0

Answer:

A.-12x^2-5x-102

Step-by-step explanation:

We are given a polynomial of degree 2 where terms are not grouped and simplified.

We have

-21x^2+22x^2-13x^2-10x+5x-102

To get this in proper form we have to group the like terms first

x^2 term = -21x^2+22x^2-13x^2 = x^2 (-21+22-13)

= x^2(-34+22) = -12x^2

x terms are -10x+5x = x(-10+5) = -5x

Constant term is only one = -102

Hence the polynomial in simplified form is

-12x^2-5x-102


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Step-by-step explanation:

Given

  • u = ⟨2, –3⟩
  • v = ⟨1, –1⟩

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

Next, find the lengths of the vectors:

\mathrm{Computing\:the\:Euclidean\:Length\:of\:a\:vector}:\quad \left|\left(x_1\:,\:\:\ldots \:,\:\:x_n\right)\right|=\sqrt{\sum _{i=1}^n\left|x_i\right|^2}

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\:\:\left|u\right|\:=\sqrt{2^2+\left(-3\right)^2}

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u = ⟨2, –3⟩

|v|=\sqrt{1^2+\left(-1\right)^2}

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Finally, the angle is given by:

\mathrm{Computing\:the\:angle\:between\:the\:vectors}:\quad \cos \left(\theta \right)\:=\frac{\vec{a\:}\cdot \vec{b\:}}{\left|\vec{a\:}\right|\cdot \left|\vec{b\:}\right|}

cos (Ф) = 5/√26

Ф = arc cos (cos (Ф)) = arc cos (5 √26) / (26)

Ф = 11.30°

Thus, the measure of the angle between the vectors = Ф = 11.30°

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