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pentagon [3]
3 years ago
8

What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

<em><u>Question:</u></em>

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>Answer:</u></em>

<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>

y = \frac{4}{3}x + 2

<em><u>Solution:</u></em>

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

<em><u>Given equation is:</u></em>

4x - 3y = 21

Rearrange,

3y = 4x - 21

y = \frac{4}{3}x - \frac{21}{3}\\\\y = \frac{4}{3}x - 7

On comparing above equation with eqn 1,

m = \frac{4}{3}

We know that slopes of parallel lines are same

Therefore, slope of line parallel to the line 4x - 3y = 21 is 4/3

<em><u>Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1</u></em>

6 = \frac{4}{3} \times 3 + c\\\\6 = 4 + c\\\\c = 2

<em><u>Substitute c = 2 and m = 4/3 in eqn 1</u></em>

y = \frac{4}{3}x + 2

Thus the equation of line is found

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16

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8 0
3 years ago
What is the 150th term in this sequence? 17, 162, 16, 15....​
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3 years ago
What is the nth term rule of the quadratic sequence below?
Vladimir [108]

Answer:

3n² + 5n - 2

Step-by-step explanation:

<u>Given sequence</u>:

6, 20, 40, 66, 98, 136, ...

Calculate the <u>first differences</u> between the terms:

6 \underset{+14}{\longrightarrow} 20 \underset{+20}{\longrightarrow} 40 \underset{+26}{\longrightarrow} 66 \underset{+32}{\longrightarrow} 98 \underset{+38}{\longrightarrow} 136

As the first differences are not the same, calculate the <u>second differences:</u>

14 \underset{+6}{\longrightarrow} 20 \underset{+6}{\longrightarrow} 26 \underset{+6}{\longrightarrow} 32 \underset{+6}{\longrightarrow} 38

As the <u>second differences are the same</u>, the sequence is quadratic and will contain an n² term.

The <u>coefficient</u> of the n² term is <u>half of the second difference</u>.

Therefore, the n² term is:  3n²

Compare 3n² with the given sequence:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2 & 3 & 12 & 27 & 48 \\\cline{1-5} \sf operation & +3&+8 & +13 & +18 \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

The second operations are different, therefore calculate the differences <em>between</em> the second operations:

3 \underset{+5}{\longrightarrow} 8 \underset{+5}{\longrightarrow} 13\underset{+5}{\longrightarrow} 18

As the differences are the same, we need to add 5n as the second operation:

\begin{array}{|c|c|c|c|c|}\cline{1-5} n & 1 & 2 & 3 & 4\\\cline{1-5} 3n^2  +5n & 8&22 & 42 & 68\\\cline{1-5}\sf operation & -2 &-2  &-2  & -2  \\\cline{1-5} \sf sequence & 6 & 20 & 40 & 66\\\cline{1-5}\end{array}

Finally, we can clearly see that the operation to get from 3n² + 5n to the given sequence is to subtract 2.

Therefore, the nth term of the quadratic sequence is:

3n² + 5n - 2

6 0
1 year ago
alison, beatrice and chole each had some books. alison gave beatrice and chole some books that doubled the number of books they
slamgirl [31]

alison, beatrice and chole each of them have at first 56, 8, 32 books.

alison, beatrice and chole each had some books. alison gave beatrice and chole some books that doubled the number of books they had, lastly chole gave alison and beatrice some books that doubled the number of books they had. each of them had 32 books at the end.

<h3>What is Working backward?</h3>

Working backward is process in which calculation done in reverse direction.

let alison, beatrice and chole has x,y and z books initially,

alison gave beatrice and chole some books that doubled the number of books they had
alison, beatrice and chole has (96-2y-2z), (2y) , (2z)
chole gave alison and beatrice some books that doubled the number of books they had. each of them had 32 books at the end.

alison, beatrice and chole has 2(96-2y-2z), 2(2y) , (96-2(96-2y-2z)-4y)

at the end,
beatrice = 32

4y=32

y = 8

chole =32

96-2(96-2y-2z)-4y)=32
z=32

alison = 96-y-z

x=96-8-32
x=56

Thus the required alison, beatrice and chole each of them have at first 56, 8, 32 books.

Learn more about working backward here:

brainly.com/question/14636831

#SPJ1



8 0
2 years ago
HELP! I don't understand so please give a detailed explanation.
likoan [24]

From the picture, we can see that ΔLSP and ΔLRN are similar, so corresponding sides are proportionate:


LN : LP = 28:12 = 7:3


Therefore, the LRN sides is 7/3 of the corresponding side of LSP.


Then, it states that the area of LSP = 50, and area of a triangle is (1/2)bh, so we set up the equation


Area of LSP = (1/2)bh = 50 ← Remember how the corresponding sides are 7/3 of LSP? Therefore, the area of LRN:


LRN = (1/2)(7b/3)(7h/3) ← Take out the 7/3 and multiply them together

= (49/9)(1/2)bh ← From LSP, we know that (1/2)bh = 50, so plug that in

= (49/9)*50 ≈ 272.222 units ²

6 0
3 years ago
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