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pentagon [3]
3 years ago
8

What is an equation of the line that passes through the point (3,6)(3,6) and is parallel to the line 4x-3y=214x−3y=21?

Mathematics
1 answer:
polet [3.4K]3 years ago
4 0

<em><u>Question:</u></em>

What is an equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>Answer:</u></em>

<em><u>The equation of the line that passes through the point (3,6) and is parallel to the line 4x-3y=21 is:</u></em>

y = \frac{4}{3}x + 2

<em><u>Solution:</u></em>

Given that line passes through the point (3,6) and is parallel to the line 4x-3y=21

<em><u>The equation of line in slope intercept form is given as:</u></em>

y = mx + c ------- eqn 1

Where, "m" is the slope and "c" is the y intercept

<em><u>Given equation is:</u></em>

4x - 3y = 21

Rearrange,

3y = 4x - 21

y = \frac{4}{3}x - \frac{21}{3}\\\\y = \frac{4}{3}x - 7

On comparing above equation with eqn 1,

m = \frac{4}{3}

We know that slopes of parallel lines are same

Therefore, slope of line parallel to the line 4x - 3y = 21 is 4/3

<em><u>Substitute m = 4/3 and (x, y) = (3, 6) in eqn 1</u></em>

6 = \frac{4}{3} \times 3 + c\\\\6 = 4 + c\\\\c = 2

<em><u>Substitute c = 2 and m = 4/3 in eqn 1</u></em>

y = \frac{4}{3}x + 2

Thus the equation of line is found

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